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QveST [7]
3 years ago
15

If f(x)=sinx−1/cos2x, then limx→π2f(x) is equivalent to which of the following?

Mathematics
1 answer:
Harrizon [31]3 years ago
8 0

Answer:

2

Step-by-step explanation:

Given g(x) = sin(x)-1/cos2(x), we are to find the limit if the function g(x) as g(x) tends to π/2

Substituting π/2 into the function

lim x-->π/2 sin(x)-1/cos 2(x)

= sin(π/2) - 1/cos(2)(π/2)

= 1 - 1/cosπ

= 1- 1/-1

= 1 -(-1)

= 1+1

= 2

Hence the limit of the function h(x) = sin(x)-1/cos2(x) as x--> π/2 is 2

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I think the answer is c

4 0
3 years ago
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Three times the sum of a number and two<br><br>3(2) + x<br><br>3(x+2)<br><br>3x + 2<br><br>2(x + 3)​
rodikova [14]

Answer:

3x + 2 =2x 3x = 2x - 2 3x - 2x = -2 x = -2 Proof: 3 * -2 + 2 = 2 * -2 -4 = -4

Step-by-step explanation:

3 0
3 years ago
Which of the following functions f : {0, 1, 2, 3} ! {0, 1, . . . , 7} are one-to-one?
allsm [11]

Answer:

1. No.

f(0)=0\\1^2=1; \text{then } f(1)=1\\2^2=4\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^2=9\equiv 1 \text{mod 8 }; \text{then } f(3)=1

Since f(1)=f(3) and 1\neq 3 then f isn't one-to-one.

2. No

f(0)=0\\1^3=1\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3=8\equiv 0\text{ mod 8}; \text{then } f(2)=0\\3^3=27\equiv 3 \text{ mod 8}; \text{then } f(3)=3

Since f(0)=f(2) and 0\neq 2 then f isn't one-to-one.

3. No

0^3-8=-8\equiv 0\text{ mod 8}; \text{then } f(0)=0\\1^3-8=-7\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3-8=0\equiv 0 \text{ mod 8}; \text{then } f(2)=0\\3^3-8=27-8=19\equiv 3 \text{ mod 8}; \text{then } f(3)=3\\

Since f(0)=f(2) and 0\neq 2 then f isn't one-to-one.

4. Yes

0^3+2*0=0; \text{then } f(0)=0\\1^3+2*1=3\equiv 3\text{ mod 8};  \text{then } f(1)=3\\2^3+2*2=8+4=12\equiv 4 \text{ mod 8};  \text{then } f(2)=4\\3^3+2*3=27+6=33\equiv 1\text{ mod 8};  \text{then } f(3)=1

Since f(0)\neq f(1)\neq f(2) \neq f(3), then f is one-to-one

5. Since f(1)=f(3) and 1\neq 3 then, f isn't one-to-one

3 0
3 years ago
5•x=12 help me help me!
Zarrin [17]

Answer:

x=2.4

Step-by-step explanation:

5·x=5x

5x=12

12/5=2.4

x=2.4

4 0
3 years ago
There are 480 soccer balls on a field. Every hour, half of the balls are put back into the locker room. Write an equation that c
Mrac [35]

Answer:

y= 480-0.5x

Step-by-step explanation:

Given data

Number of balls= 480

we are told that 50%(half) of the balls are put back every 1

let the number of hours be x

and let the remaining ball be y after x hours

Hence the expression is given as

y= 480-0.5x

3 0
3 years ago
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