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OLga [1]
3 years ago
8

an element has a metallic gray appearance. it also has the properties of both a metal and a nonmetal. in which section of the pe

riodic table indicated above would the element most likely be found?

Chemistry
1 answer:
irinina [24]3 years ago
6 0
If it has properties of metal and non metal it is considered a metalloid there are very few spots in which metalloids are located the spots I circled on a blank periodic tables are where the metalloids are located on an actual periodic table your only options are
boron(B) silicon(si) germanium(Ge) arsenic(As)antimony(Sb)tellurium(Te)astatine(At)those are the only places on the periodic table that has metalloids... I hope this helps

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How would you prepare 250 mL of 0.125 M HCl from concentrated HCl (aq) that is 38.0% by mass with a density of 1.19 g/mL
hoa [83]
<h2>Step 1 : Identify the given </h2>

Volume = 250mL

Density = 1.19 g/ML

<h2>Step 2 . Calculate the mass of HCL </h2>

Density = mass/volume

∴Mass = Density * Volume

= 1.19g/mL* 250mL

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<h2>Step 3 : Calculate the total mass of the solution, given that concentration HCL is 38% </h2>

Mass of the total solution can be calculated by the following :

38% = Mc /297.5 * 100

Mc = 38/100 *297.5

= 113.05grams

• Finally, this means that mass of the total solution of 0.125M HCL i,s 113grams, ,you would use this mass to prepare 250 mL of 0.125 M HCl from concentrated HCl (aq) that is 38.0%

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1 year ago
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What is the molarity of a solution that is made by mixing 35.5 g of Ba(OH)2 in 325 ml of solution?
choli [55]

Answer:

M=0.638M

Explanation:

Hello!

In this case, since the molarity of a solution is calculated by diving the moles of solute by the volume of solution in liters, we first compute the moles of barium hydroxide in 35.5 g as shown below:

n=35.5g Ba(OH)_2*\frac{1molBa(OH)_2}{171.34gBa(OH)_2}\\\\n=0.207mol

Then, the liters of solution:

V=325mL*\frac{1L}{1000mL} =0.325L

Finally, the molarity turns out:

M=\frac{0.207mol}{0.325L}\\\\M=0.638M

Best regards!

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