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3 years ago

What effects does hemlock have on victim?

Chemistry

1 answer:

MrMuchimi3 years ago

8 0

Answer:

Hemlock contains poisons that affect the transmission of nerve impulses to muscle. Death occurs by respiratory failure.

Explanation:

Hemlock is a very poisonous plant. In fact, all parts of the plant are toxic. Hemlock is most poisonous during the early stages of growth in the spring, but it is dangerous at all stages of growth. The poisons in hemlock are so deadly that people have died after eating game birds that had eaten hemlock seeds.

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What is the answer of this question?

aleksley [76]

Answer:

mass =density multiplied by volume

6 0

3 years ago

Which phrase describes a hypothesis? a. reviewing information related to the problem b. testing a factor, or variable, in an exp

monitta

Answer:

c. suggesting a solution to a problem after studying it carefully

Explanation:

Hypothesis generally refers to an assumption made. This assumption can either be true or false. It is a reasoning presented in order to explain a phenomenon and is the starting point for further investigation.

Among the options, the closest that best describes it is option C.

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3 years ago

Are inner planets rockier or more like gas??

Eduardwww [97]

Inner planets are rockier and outer planets are gaseous. Hope this helps! Can I have brainliest please

4 0

3 years ago

Read 2 more answers

Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t

Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

$(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)$

Now we have to calculate the amount of heat released or absorbed in both processes.

<u>For process 1 :</u>

$Q_1=m\times \Delta H_{fusion}$

where,

$Q_1$ = amount of heat absorbed = ?

m = mass of water or ice = 1.0 Kg

$\Delta H_{fusion}$ = enthalpy change for fusion = $3.35\times 10^5J/Kg$

Now put all the given values in $Q_1$ , we get:

$Q_1=1.0Kg\times 3.35\times 10^5J/Kg=3.35\times 10^5J$

<u>For process 2 :</u>

$Q_2=m\times c_{p,l}\times (T_{final}-T_{initial})$

where,

$Q_2$ = amount of heat absorbed = ?

m = mass of water = 1.0 Kg

$c_{p,l}$ = specific heat of liquid water = $4186J/Kg^oC$

$T_1$ = initial temperature = $0^oC$

$T_2$ = final temperature = $100^oC$

Now put all the given values in $Q_2$ , we get:

$Q_2=1.0Kg\times 4186J/Kg^oC\times (100-0)^oC$

$Q_2=4.186\times 10^5J$

From this we conclude that, $Q_1$ that means it takes less amount of heat to metal 1.0 Kg of ice.

Hence, the it takes less amount of heat to metal 1.0 Kg of ice.

5 0

3 years ago

Please Need help asap

ruslelena [56]

Answer:

Explanation:

The number of protons and neutrons of an element is the same. the electrons are the only thing that can differ. The atomic number equal the protons and neutrons.

4 0

2 years ago