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2 years ago

Which Earth motion describes the wobbling of the Earth around its precessional axis and

Chemistry

1 answer:

Alexeev081 [22]2 years ago

3 0

Answer:

Nutation

Explanation:

The counterclockwise rotation of planet earth around its own axis is defined as the Earth Rotation. The earth rotates about the line called "the axis of rotation," it is an imaginary line that passes through the North and South Poles of the planet, which the earth rotates about.

Hence, earth rotates once in about 24 hours with respect to the Sun, from West to East and thus giving rise to;

a. Day and night

b. Seasons

The Earth motion which describes the wobbling of the Earth around its precessional axis and could alter the amount of seasonal effects is known as nutation.

Basically, nutation usually occurs when the precessional motion of a planetary body such as planet earth experience some form of irregularities when it is rotating.

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In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for

inessss [21]

Answer:

The standard cell potential of the reaction is 0.78 Volts.

Explanation:

$Cu^{2+}(aq)+Fe(s)\rightarrow Cu(s)+Fe^{2+}(aq)$

Reduction at cathode :

$Cu^+(aq)+2e^-\rightarrow Cu(s)$

Reduction potential of $Cu^{2+}$ to Cu= $E^o_{1}=0.34 V$

Oxidation at anode:

$Fe(s)\rightarrow Fe^{2+}(aq)+2e^-$

Reduction potential of $Fe^{2+}$ to Fe= $E^o_{2}=-0.44 V$

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}$

Putting values in above equation, we get:

$E^o_{cell}=0.34V -(-0.44 V)=0.78 V$

The standard cell potential of the reaction is 0.78 Volts.

3 0

3 years ago

Help this is due soon!!!

denis23 [38]

Answer:

not 100% sure but I think it's unbalanced chemical

6 0

3 years ago

Calculate the percent composition for each element in each of the following compounds.

jek_recluse [69]

The answer is c because the calculations for the elements have to connect with the compounds

6 0

3 years ago

A mixture that separates into different layers when you stop stirring it is Select one: a. a solution. b. a suspension. c. a col

leva [86]

Answer: b suspension

a suspension is a heterogeneous mixture that contains solid particles sufficiently large for sedimentation . The particles may be

visible to the naked eye, usually must be larger than one micrometer , and will eventually settle, although the mixture is only classified as a suspension when and while the particles have not settled out. A suspension is a heterogeneous mixture in which the solute particles do not dissolve , but get suspended throughout the bulk of the solvent , left floating around freely in the medium. [1] The internal phase (solid) is dispersed throughout the external phase (fluid) through mechanical agitation , with the use of certain excipients or suspending agents.

An example of a suspension would be sand in water. The suspended particles are visible under a

microscope and will settle over time if left undisturbed. This distinguishes a suspension from a colloid , in which the suspended particles are smaller and do not settle.

Colloids and suspensions are different from

solution , in which the dissolved substance (solute) does not exist as a solid, and solvent and solute are homogeneously mixed.

8 0

3 years ago

Write the balanced standard combustion reaction for the c5h7on3s2

AlexFokin [52]

Answer:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Explanation:

When C5H7ON3S2 under go Combustion, the following are obtained as illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

Now, let us balance the equation. This is illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

There are 3 atoms of N on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of C5H7ON3S2 and 6 in front of N2 as shown below:

4C5H7ON3S2 + O2 —> CO2 + H2O + 6N2 + S2

There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + H2O + 6N2 + S2

There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + S2

There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

4 0

2 years ago