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3 years ago

1.

Chemistry

1 answer:

IceJOKER [234]3 years ago

4 0

Answer:

565 kJ

Explanation:

$H_v$ = Heat of vaporization of water at 100°C = 2260 J/g

m = Mass of water = 250 g

Heat required is given by

$Q=mH_v$

$\Rightarrow Q=250\times 2260$

$\Rightarrow Q=565000\ \text{J}$

$\Rightarrow Q=565\times 10^3\ \text{J}$

$\Rightarrow Q=565\ \text{kJ}$

The heat required to vaporize the water is 565 kJ.

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