Answer:
The bowlling shell's thickness is 2.7"
Explanation:
The geometry of the problem is based in the differences between the volumes in a small sphere and a spherical shell, both objects compose the total volume of the bowling ball.
The equivalence in the total ball height and the equivalent height in the fluid (in this case water displacement of half ball volume) is used for calculating the forces state that allows the static balance of the ball and the flotation force from the fluid (Archimedes principle).
In the image is showed the formulation.
<span>Torque can be calculated by multiplying the force and the "perpendicular distance"
Hope this helps!</span>
DEFINITION
The light stripes are regions of high clouds, and the dark stripes are regions where we can see down to deeper, darker clouds.
GOES WITH
Which of the following best why we see horizontal "stripes" in photographs of Jupiter and Saturn?
Answer:
I believe it is not a chemical change for the components are not changing.
This excerpt from thoughtco.com states that for it to be a chemical change, the atoms would be rearranged.
<em>In other words, a chemical change is a chemical reaction involving the rearrangement of atoms. While a physical change can often be reversed, a chemically change typically cannot be, except through more chemical reactions. When a chemical change occurs, there is also a change in the energy of the system.</em>
So, in this case, they are not being rearranged, just combined to form one big fruit salad.
Answer:
Explanation:
For rolling up or down an incline plane , the acceleration or deceleration of the rolling body is given by the following expression
a = g sinθ / (1 + k²/r² )
where k is radius of gyration of rolling body and θ is angle of inclination
a = g sin15 / ( 1 + 1 ) [ for hoop k = r ]
a = 9.8 x .2588 / 2
= 1.268 m / s²
a )
Let s be the distance up to which it goes
v² = u² - 2as
0 = 3.3² - 2 x 1.268 s
s = 4.3 m
b ) Let time in going up be t₁
v = u - at₁
0 = 3.3 - 1.268 t₁
t₁ = 2.6 s
Time in going down t₂
s = 1/2 a t₂²
4.3 = .5 x 1.268 t₂²
t₂ = 2.60
Total time
= t₁ +t₂
= 2.6 + 2.6
= 5.2 s
