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Katarina [22]
3 years ago
15

A convex lens focuses light to a single focal point. What wave behavior is responsible for the light rays coming together at the

focal point?
Here is the photo.

https://lh5.googleusercontent.com/eh8oGTs-v3tx_mRRUCrXEn6z1Zs8nl7V1BMaNagYhXHO2LJ7KD6KoGFVJoedU5ZrV_QJINPziBmDDYIyrN5YiPR2fqIsUVjnRKK5jBdPxY03KVOaFi46KADJ-ArS=w314


Answer choices:

A-Reflection

B-Refraction

C-Absorption

D-Diffraction

Physics
1 answer:
dem82 [27]3 years ago
7 0

Answer:

B-Refraction  

Explanation:

Refraction is the change in direction of a wave as it passes from one medium to another.

The curved surface of a convex lens bends the light rays just enough to make them meet at a focal point.

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Read 2 more answers
A uranium and iron atom reside a distance R = 44.10 nm apart. The uranium atom is singly ionized; the iron atom is doubly ionize
Ad libitum [116K]

Answer:

distance r from the uranium atom is 18.27 nm

Explanation:

given data

uranium and iron atom distance R = 44.10 nm

uranium atom = singly ionized

iron atom = doubly ionized

to find out

distance r from the uranium atom

solution

we consider here that uranium electron at distance = r

and electron between uranium and iron so here

so we can say electron and iron  distance = ( 44.10 - r ) nm

and we know single ionized uranium charge q2= 1.602 × 10^{-19} C

and charge on iron will be q3 = 2 × 1.602 × 10^{-19} C

so charge on electron is q1 =  - 1.602 × 10^{-19} C

and we know F = k\frac{q*q}{r^{2} }  

so now by equilibrium

Fu = Fi

k\frac{q*q}{r^{2} }  =  k\frac{q*q}{r^{2} }

put here k = 9*10^{9} and find r

9*10^{9}\frac{1.602 *10^{-19}*1.602 *10^{-19}}{r^{2} }  =  9*10^{9}\frac{1.602 *10^{-19}*1.602 *10^{-19}}{(44.10-r)^{2} }

\frac{1}{r^{2} } = \frac{2}{(44.10 -r)^2}

r = 18.27 nm

distance r from the uranium atom is 18.27 nm

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