When resistance force on a lever increases, nothing happens automatically.
But if you want to keep lifting the load, then YOU must increase the force of
your effort in order to make it happen.
Explanation:
If g= 10m/s²
Then 75kg=75×10=750N
Since Work =Force ×Distance
Work=750×30
=22500J
And Power°=Work÷time
=22500÷120
=187.5W
Answer:
M = 6.32 x 10⁻⁶ H
Explanation:
given,
Length of solenoid = 10 cm = 0.1 m
diameter = 0.40 cm
radius = 0.2 cm = 0.002
number of turns, N₁ = 800
N₂ = 50
mutual inductance will be equal to
M = 6.32 x 10⁻⁶ H
hence, mutual inductance of the combination of two coil is equal to M = 6.32 x 10⁻⁶ H
Answer:
8 kV
Explanation:
Here is the complete question
Assume a device is designed to obtain a large potential difference by first charging a bank of capacitors connected in parallel and then activating a switch arrangement that in effect disconnects the capacitors from the charging source and from each other and reconnects them all in a series arrangement. The group of charged capacitors is then discharged in series. What is the maximum potential difference that can be obtained in this manner by using ten 500 μF capacitors and an 800−V charging source?
Solution
Since the capacitors are initially connected in parallel, the same voltage of 800 V is applied to each capacitor. The charge on each capacitor Q = CV where C = capacitance = 500 μF and V = voltage = 800 V
So, Q = CV
= 500 × 10⁻⁶ F × 800 V
= 400000 × 10⁻⁶ C
= 0.4 C
Now, when the capacitors are connected in series and the voltage disconnected, the voltage across is capacitor is gotten from Q = CV
V = Q/C
= 0.4 C/500 × 10⁻⁶ F
= 0.0008 × 10⁶ V
= 800 V
The total voltage obtained across the ten capacitors is thus V' = 10V (the voltages are summed up since the capacitors are in series)
= 10 × 800 V
= 8000 V
= 8 kV
Yeah I conclude that the answer is A because it need distance but with out charge it would no get that distance so yeah A
