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sweet-ann [11.9K]

3 years ago

5

In _____, marketers determine price based on what consumers are willing to pay and then subtract desired margins to yield target

costs.
Select one:
a. cost-based pricing
b. demand-based pricing
c. gap-determined pricing
d. fixed-margin pricing

1 answer:

Alona [7]3 years ago

3 0

I would have to say "a. cost-based pricing"

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How many football fields (including the 10 yards in each end zone) would it take to make a mile?

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Answer:

Explanation:

1760 yd/mi / 120 yd/field = 14⅔ fields/mi

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3 years ago

A 263 g ball of clay falls onto a vertical spring.

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Answer:

d. According to the previous theorem:

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3 years ago

Metals can be described as?

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3 years ago

X-rays with frequency 3 ⨉ 10 18 Hz shine on a crystal, producing an interference pattern. If the first bright spot is observed a

FrozenT [24]

Answer:

$5.1645\times 10^{-11}\ m$

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f = Frequency = $3\times 10^{18}\ Hz$

$\theta$ = Angle = $75.5^{\circ}$

Lattice spacing is given by

$d=\dfrac{n\lambda}{2\sin\theta}\\\Rightarrow d=\dfrac{n\times c}{f2\sin\theta}\\\Rightarrow d=\dfrac{1\times 3\times 10^{8}}{3\times 10^{18}\times 2\times \sin75.5^{\circ}}\\\Rightarrow d=5.1645\times 10^{-11}\ m$

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6 0

3 years ago

A 50.0 kg object is moving at 18.2 m/s when a 200 N force

gayaneshka [121]

Answer:

distance = 21.56 m

Explanation:

given data

mass = 50 kg

initial velocity = 18.2 m/s

force = -200 N ( here force applied to opposite direction )

final velocity = 12.6 m/s

solution

we know here acceleration will be as

acceleration a = force ÷ mass

a = $\frac{-200}{50}$ = -4 m/s²

we get here now required time that is

required time = $\frac{V_{(final)} - V_{(initial)}}{a}$ ...............1

put here value

required time = $\frac{12.6-18.2}{-4}$

so distance will be

distance = $\frac{V_{(final)}^2 - V_{(initial)}^2}{2a}$ ........2

distance = $\frac{12.6}^2 -{18.2}^2}{2\times (-4)}$

distance = 21.56 m

7 0

3 years ago