Answer:
The horizontal range will be 
Explanation:
We have given initial speed of the shell u = 
Angle of projection = 51°
Acceleration due to gravity 
We have to find maximum range
Horizontal range in projectile motion is given by

So the horizontal range will be 
Answer:
2/B
6/E
7/F
12/6
Explanation:
Hope this helps i dont know ither i will put if i think of them
Given :
An object with a volume of 9 cm³ is completely submerged in the water.
To Find :
How much water is displaced by the object.
Solution :
According to Archimedes' principle, the amount of volume displaced of fluid when an object is fully and partially submerged into that is equal to the volume of the object below the surface of liquid.
Now, it is given that object is fully submerged into water.
Therefore, volume of water displaced by the object is 9 cm³.
Stars are not really planets because they are far, far away from our solar system.
Hope this is helpful~
I think this might be the answer let me know 0.2 g/cm^3