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sweet-ann [11.9K]
3 years ago
5

In _____, marketers determine price based on what consumers are willing to pay and then subtract desired margins to yield target

costs.
Select one:
a. cost-based pricing
b. demand-based pricing
c. gap-determined pricing
d. fixed-margin pricing
Physics
1 answer:
Alona [7]3 years ago
3 0
I would have to say "a. cost-based pricing"
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How many football fields (including the 10 yards in each end zone) would it take to make a mile?
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Answer:

Explanation:

1760 yd/mi / 120 yd/field = 14⅔ fields/mi

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3 years ago
A 263 g ball of clay falls onto a vertical spring.
Elena-2011 [213]

Answer:

d. According to the previous theorem:

(kh^2)/2-mgh-(m(2v)^2)/2=0,

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3 years ago
Metals can be described as?
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3 years ago
X-rays with frequency 3 ⨉ 10 18 Hz shine on a crystal, producing an interference pattern. If the first bright spot is observed a
FrozenT [24]

Answer:

5.1645\times 10^{-11}\ m

Explanation:

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f = Frequency = 3\times 10^{18}\ Hz

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Lattice spacing is given by

d=\dfrac{n\lambda}{2\sin\theta}\\\Rightarrow d=\dfrac{n\times c}{f2\sin\theta}\\\Rightarrow d=\dfrac{1\times 3\times 10^{8}}{3\times 10^{18}\times 2\times \sin75.5^{\circ}}\\\Rightarrow d=5.1645\times 10^{-11}\ m

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6 0
3 years ago
A 50.0 kg object is moving at 18.2 m/s when a 200 N force
gayaneshka [121]

Answer:

distance = 21.56 m

Explanation:

given data

mass = 50 kg

initial velocity  = 18.2 m/s

force = -200 N ( here force applied to opposite direction )

final velocity = 12.6 m/s

solution

we know here acceleration will be as

acceleration a  = force ÷ mass

a = \frac{-200}{50}   =  -4 m/s²

we get here now required time that is

required time = \frac{V_{(final)} - V_{(initial)}}{a}     ...............1

put here value

required time = \frac{12.6-18.2}{-4}  

so distance will be

distance = \frac{V_{(final)}^2 - V_{(initial)}^2}{2a}    ........2

distance = \frac{12.6}^2 -{18.2}^2}{2\times (-4)}  

distance = 21.56 m

7 0
3 years ago
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