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CaHeK987 [17]
3 years ago
15

43. Simplify (k – 5) - (k2 + 8).

Mathematics
2 answers:
CaHeK987 [17]3 years ago
4 0

Answer:

D.-k^2+k-13

Step-by-step explanation:

(k-5)-(k^2+8)

Expand the brackets. Remember brackets mean to multiply.

k*k^2= k^2+k

-5*+8= -13

Add values together.

k^2+k-13

lesantik [10]3 years ago
3 0

Answer:

(D) -k2 + k - 13

Step-by-step explanation:

Pulling out like terms :

2.1     Pull out like factors :

  -k2 + k - 13  =   -1 • (k2 - k + 13)

Trying to factor by splitting the middle term

2.2     Factoring  k2 - k + 13

The first term is,  k2  its coefficient is  1 .

The middle term is,  -k  its coefficient is  -1 .

The last term, "the constant", is  +13

Step-1 : Multiply the coefficient of the first term by the constant   1 • 13 = 13

Step-2 : Find two factors of  13  whose sum equals the coefficient of the middle term, which is   -1 .

     -13    +    -1    =    -14

     -1    +    -13    =    -14

     1    +    13    =    14

     13    +    1    =    14

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

 -k2 + k - 13

Processing ends successfully

plz mark me as brainliest :)

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Answer:

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Step-by-step explanation:

We have:

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So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

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We can move the constant outside:

\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]

Now, we will utilize the product rule. The product rule is:

(uv)^\prime=u^\prime v+u v^\prime

We will let:

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Then:

\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1

(The derivative of u was determined using the chain rule.)

Then it follows that:

\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}

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\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]

By simplification:

\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17

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