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Delicious77 [7]
2 years ago
14

What is not a phase of matter

Chemistry
2 answers:
sertanlavr [38]2 years ago
6 0

C. Condensing.

Why: Because, Condensing means  to make something denser or more concentrated.

Hope this helps! ;)

yulyashka [42]2 years ago
5 0
B I think not sure hope it’s right
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The image formed by a lens may be real or virtual. The image formed by a lens is always virtual.
amid [387]
There are types of lens; concave and convex lens.
The concave lens is a lens which has an inward curve in the middle, that is, the edges of the curve are thicker than the center of the lens, because of this, any light that enter the lens will spread out [diverge]. An image will look smaller and upright when viewed by a concave lens. Image formed by concave lens are usually VIRTUAL. 
A concave lens will produce a real image ONLY if the object is located beyond the focal point of the lens.
A convex lens is a converging lens, this is because, the center of the lens is thicker than its edges. Any ray of light that passes through the lens will converge at the middle of the lens at point called principal focus.  A convex lens produce a VIRTUAL image when the object is placed infront of the focal point. The virtual image formed is always magnified and upright.<span />
8 0
3 years ago
Read 2 more answers
Identify the compound with the highest standard free energy of formation. identify the compound with the highest standard free e
Anestetic [448]
The compound with the highest standard free energy of formation is O3(g)


7 0
3 years ago
What is the molar mass of 56.75 g of gas exerting a pressure of 2.87 atm on the walls of a 5.29 l container at 230 k?
laiz [17]
We first need to find the number of moles of gas in the container 
PV = nRT
where;
P - pressure - 2.87 atm x 101 325 Pa/atm = 290 802.75 Pa
V - volume - 5.29 x 10⁻³ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 230 K
substituting these values in the equation 
290 802.75 Pa x  5.29 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 230 K
n = 0.804 mol
the molar mass = mass present / number of moles
molar mass of gas = 56.75 g / 0.804 mol 
therefore molar mass is 70.6 g/mol 
8 0
3 years ago
How would the calculated concentration of the hci be affected if the sodium hydroxide were poured from ma beaker that contained
Mekhanik [1.2K]

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, the beaker that contained some water before NaOH were added means that the resulting solution in that beaker will be more dilute. When this diluted sodium hydroxide solution is added to HCl (not hci), the reaction below occurs

HCl + NaOH ⇒ NaCl + H₂O

The reaction above is a neutralization reaction. <u>The concentration of the acid (HCl) will reduce when a base (sodium hydroxide) is added and will also reduce more because of the presence of more water (in the base) which normally reduces the concentration of ions present in an acid or a base to become more dilute.</u>

5 0
3 years ago
You have 67.2 liters of oxygen at standard temperature and pressure. How many moles of oxygen molecules do you have? *
enot [183]

Answer:

Number of moles is 3.0moles

Explanation:

Volume (v) = 67.2L

Pressure at STP = 1atm

Temperature at STP = 273.15K

R = 0.082J/mol.K

Number of moles (n) = ?

From ideal gas equation,

PV = nRT

P = pressure

V = volume of the gas

n = number of moles

R = ideal gas constant

T = temperature of the gas

PV = nRT

solving for n,

n = PV / RT

n = (1.0 * 67.2) / (0.082 * 273.15)

n = 67.2 / 22.398

n = 3.0 moles

The number of moles present is 3.0

3 0
3 years ago
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