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Dmitry_Shevchenko [17]
4 years ago
7

Which is the fundamental law of energy?

Chemistry
2 answers:
Paraphin [41]4 years ago
6 0
The first law<span>, also known as </span>Law<span> of Conservation of </span>Energy<span>, states that </span>energy <span>cannot be created or destroyed in an isolated system.</span><span> 
So answer 1</span>
Usimov [2.4K]4 years ago
3 0
Energy can be transferred but cannot be destroyed!
You might be interested in
1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium
lilavasa [31]

Answer:

This question is incomplete, here's the complete question:

1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium ion present in 20.0 mL of each buffer.

Buffer A

Mass of sodium acetate used: 0.3730 g

Actual ph of the buffer 5.27

volume of the buffer used in buffer capacity titration 20.0 mL

Concentration of standardized NaOH 0.100M

moles of Naoh needed to change the ph by 1 unit for the buffer 0.00095mol

the buffer capacity 0.0475 M

Buffer B

Mass of sodium acetate used 1.12 g

Actual pH of the buffer 5.34

Volume of the buffer used in buffer capacity titration 20.0 mL

Concentration if standardized NaOH 0.100 M

moles of Naoh needed to change the ph by 1 unit 0.0019 mol

the buffer capacity 0.095 M

2.) A change of pH by 1 unit means a change in hydronium ion concentration by a factor of 10. Calculate the number of moles of NaOH that would theoretically be needed to decrease the moles of hydronium you calculated in #1 by a factor of 10 for each buffer. Are there any differences between your experimental results and the theoretical calculation?

3.) which buffer had a higher buffer capacity? Why?

Explanation:

Formula,

moles = grams/molar mass

molarity = moles/L of solution

1. Buffer A

molarity of NaC2H3O2 = 0.3731 g/82.03 g/mol x 0.02 L = 0.23 M

molarity of HC2H3O2 = 0. 1 M

Initial pH

pH = pKa + log(base/acid)

= 4.74 + log(0.23/0.1)

= 5.10

pH = -log[H3O+]

[H3O+] = 7.91 x 10^-6 M

In 20 ml buffer,

moles of H3O+ = 7.91 x 10^-6 M x 0.02 L

= 1.58 x 10^-7 mol

Buffer B

molarity of NaC2H3O2 = 1.12 g/82.03 g/mol x 0.02 L = 0.68 M

molarity of HC2H3O2 = 0.3 M

Initial pH

pH = pKa + log(base/acid)

= 4.74 + log(0.68/0.3)

= 5.10

pH = -log[H3O+]

[H3O+] = 7.91 x 10^-6 M

In 20 ml buffer,

moles of H3O+ = 7.91 x 10^-6 M x 0.02 L

= 1.58 x 10^-7 mol

2. let x moles of NaOH is added,

Buffer A,

pH = 5.10

[H3O+] = 7.91 x 10^-6 M

new pH = 4.10

new [H3O+] = 7.91 x 10^-5 M

moles of NaOH to be added = (7.91 x 10^-5 - 7.91 x 10^-6) x 0.02 L

= 1.42 x 10^-6 mol

3. Buffer B with greater concentration of NaC2H3O2 and HC2H3O2 has higher buffer capacity as it resists pH change to a wider range due to addition of acid or base to the system as compared to low concentration of Buffer A

5 0
3 years ago
A balloon is inflated to a volume of 7.0 L 7.0 L on a day when the atmospheric pressure is 765 mmHg. The next day, as a storm fr
kirill115 [55]

Answer:

The new volume is 7.27 L

Explanation:

Step 1: Data given

The initial volume of the balloon = 7.0 L

The pressure = 765 mmHg = 765/760 atm = 1.00658 atm

The pressure drops to 737 mmHg = 737/ 760 atm = 0.969737

The temperature remains constant

Step 2: Calculate the new volume

P1*V1 = P2*V2

⇒with P1 = the initial pressure in the balloon = 765 mmHg

⇒with V1 = the initial volume = 7.0L

⇒with P2 = the decreased pressure = 737 mmHg

⇒with V2 = the new volume = TO BE DETERMINED

765 mmHg * 7.0 L = 737 mmHG * V2

V2 = (765 mmHG * 7.0 L) / 737 mmHG

V2 = 7.27 L

The new volume is 7.27 L

6 0
3 years ago
How many atoms are ln 6.31 moI of sodium sulfate
Art [367]
896.27
One mole of sodium sulfate is 143.04, so just multiply that times 6.31.
I may be wrong call me out if I am
6 0
3 years ago
Read 2 more answers
The reaction between iron(II) oxide and carbon monoxide produces iron and carbon dioxide. How many moles of iron can be obtained
My name is Ann [436]

Answer:

4.75 moles of Fe

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

FeO + CO —> Fe + CO2

Now, we can determine the number of mole of iron, Fe produced by the reaction of 4.75 mol of FeO with excess CO as follow:

From the balanced equation above,

1 mole of FeO reacted to produce 1 mole of Fe.

Therefore, 4.75 moles of FeO will also react to produce 4.75 moles of Fe.

Therefore, 4.75 moles of Fe is produced.

4 0
3 years ago
Elements are simple ___
storchak [24]

Answer:

particles

atoms

broken

isotope

conductors

electricity

element

combined

3 0
3 years ago
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