Answer : The percent yield of the reaction is, 68.2 %
Explanation : Given,
Mass of = 90.0 g
Mass of = 41.0 g
Molar mass of = 60.08 g/mol
Molar mass of = 40.11 g/mol
First we have to calculate the moles of
Now we have to calculate the moles of
The balanced chemical equation is:
From the reaction, we conclude that
As, 1 mole of react to give 1 mole of
So, 1.498 mole of react to give 1.498 mole of
Now we have to calculate the mass of
Now we have to calculate the percent yield of the reaction.
Experimental yield = 41.0 g
Theoretical yield = 60.08 g
Now put all the given values in this formula, we get:
Therefore, the percent yield of the reaction is, 68.2 %