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4 years ago

8

Why do compounds with strong intermolecular attractive forces have higher boiling points than compounds with weak intermolecular

attractive forces? Provide an answer using 3 – 4 sentences and in your own words

1 answer:

Ratling [72]4 years ago

7 0

Hbxjxjnnj didn’t dudes Dixon’s

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3) Ha do vapor aod gases differ?

Neko [114]

Your question, I guess, How do vapour and gases differ...

Answer:

1.) Vapour is the changed state of any liquid either due to boiling or evaporation

2.) Vapour are more energetic as they have absorbed the latent heat of vaporization whereas Gases are low in energy because they are already in gaseous form at room temperature.

3.) Vapour have boiling points above room temperature while gases have their boiling point below room temperature.

6 0

3 years ago

Calculate the [ OH − ] and the pH of a solution with an [ H + ] = 0.090 M at 25 °C . [ OH − ] = M pH = Calculate the [ H + ] and

Valentin [98]

Answer: a) $[OH^-]=1.09\times 10^{-13}$ and pH = 1.04

b) $[H^+]=1.02\times 10^{-11}$ and $pH=10.99$

c) $[H^+]=7.08\times 10^{-11}$ and $[OH^-]=1.41\times 10^{-4}$

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

$pOH=-\log [OH^-]$

$pH+pOH=14$

a) $[H^+]=0.090M$

$pH=-\log [0.090]=1.04$

$pOH=14-1.04=12.96$

$12.96=-log[OH^-]$

$[OH^-]=1.09\times 10^{-13}$

b) $[OH^-]=0.00098M$

$pOH=-\log [0.00098]=3.01$

$pH=14-3.01=10.99$

$10.99=-log[H^+]$

$[H^+]=1.02\times 10^{-11}$

c) $pH=10.15$

$10.15=-\log [H^+]$

$[H^+]=7.08\times 10^{-11}$

$pOH=14-10.15=3.85$

$3.85=-log[OH^-]$

$[OH^-]=1.41\times 10^{-4}$

3 0

3 years ago

A 78.0 sample of gold at 175°C is put in a foam cup calorimeter with 25.0 g of water at 25.0°C. Calculate the specific heat of t

Nady [450]

The answer is the specific heat of the gold is 0.129 J/gC .

<h3>What is Calorimetry ?</h3>

It is an experimental method that allows one to calculate the heat change in a chemical process.

Calorimeter is just a reaction vessel. It could be a foam cup, a soda can, or a commercially available bomb calorimeter

Where q represents the heat change in the reaction, the calorimeter and the water. Since you are only measuring temperature, you will need to calculate the heat using it.

The change in heat of the gold is given by:

$\rm q_{gold} = m c_{gold}\Delta T$

$=78 \times c_{p}\times (175-38.18)$

The change in heat of the water is given by:

$\rm q_{water} = mc_{p}\Delta T$

m is the mass of water in the calorimeter in grams,

and delta T is the change in temperature.

where $\rm c_{p}$ is the specific heat of water, which is 4.184 J/gC

mass of water = 25 g of water.

Temperature T₁ = 25°C

Final Temperature = 38.18 °C

Difference between temperature = 13.18 °C

$\rm q_{water} = 25 \times 4.18\times 13.18$

For a Foam Cup Calorimeter

$\rm q_{water} = q_{cal}\\\\\\\rm 25\times4.18\times13.318 = 78 \times c_{p}\times (175-38.18)\\\\\\On \;solving\; this \;we \;get \;c_{p} = 0.129$

Therefore the the specific heat of the gold is 0.129 J/gC

To know more about Calorimeter

brainly.com/question/4802333

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4 0

2 years ago

How much heat is lost or gained by the calorimeter

Maslowich

Answer:

1.113 kJ or 1,113 J.

Explanation:

I hope this helps :)

5 0

3 years ago

Is corrosion of aluminum metal a chemical or physical process

nadya68 [22]

Corrosion of aluminium metal is a chemical process. Corrosion happens when a certain chemical reaction takes place.

8 0

3 years ago