Assuming the question is asking for percent composition by mass,
The molar mass of sodium bicarbonate is:
22.990 + 1.008 + 12.011 + 3*15.999 = 84.006 g/mol
The molar mass of 3 oxygen atoms is:
3*15.999 = 47.997 g/mol
The percentage composition by mass is:
47.997/84.006 * 100% = 57.1% (3 s.f.)
Answer:
Water has high heat capacity to act as a thermal buffer against freezing.
The specific heat capacity of water = 4.2 joules per gram per degree Celsius or 1 calorie per gram per degree Celsius.
So, the vats of water will help in preventing the freezing of the materilas inside.
Explanation:
The condition that will increase the entropy in a reaction is heating up the reaction (option B).
<h3>What is entropy?</h3>
Entropy in chemistry is the measure or degree of the disorder or randomness present in a chemical system.
In a chemical reaction, reacting substances called reactants collide with one another to form products.
However, the degree at which the reactants collide with one another is referred to as the entropy of the reaction.
Therefore, the condition that will increase the entropy in a reaction is heating up the reaction i.e. increase in temperature.
Learn more about entropy at: brainly.com/question/13146879
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Answer:
0.0251 M
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
HNO3 + KOH —> KNO3 + H2O
The mole ratio of the acid (nA) = 1
The mole ratio of the base (nB) = 1
Next, the data obtained from the question. This include the following:
Volume of acid (Va) = 10.1mL
Molarity of acid (Ma) =..?
Volume of base (Vb) = 61.9 mL
Molarity of base (Mb) = 0.0041 M
Next, we shall determine the molarity of the acid, HNO3 as follow:
MaVa/MbVb = nA/nB
Ma x 10.1 / 0.0041 x 61.9 = 1
Cross multiply to express in linear form
Ma x 10.1 = 0.0041 x 61.9
Divide both side by 10.1
Ma = (0.0041 x 61.9) /10.1
Ma = 0.0251 M
Therefore, the molarity of HNO3 is 0.0251 M
