Question

An observer (O) spots a bird flying at a 55° angle from a line drawn horizontal to its nest. If the distance from the observer (O) to the bird (B) is 15,000 ft., how far is the bird (B) from its nest (N)? Round to the nearest whole number. A right triangle B N O is shown with angle B marked 55 degrees, side B N marked x and side B O marked 15000 feet.

Answer 1

Answer:

x = 18311.61 m

Step-by-step explanation:

It is given that, An observer (O) spots a bird flying at a 55° angle from a line drawn horizontal to its nest. The distance from the observer (O) to the bird (B) is 15,000 ft. We need to find the distance between the bird and the nest. It is based on trigonometry. So,

$\sin (35)=\dfrac{\text{opposite}}{\text{hypotenuse}}$

Let x is the distance between the bird and the nest

So,

$\sin (55)=\dfrac{15000}{x}\\\\x=\dfrac{15000}{ \sin(55)} \\\\x=18311.61\ m$

So, the distance between the bird and the nest is 18311.61 m.