Which of following not a way to represent the solution of inequality 5(x + 2) GREATER THAN OR EQUAL TO 7x + 2(x − 1)?

Mathematics

2 answers:

mixer [17]3 years ago

6 0

So because it says NOT a way....I think it's A...Maybe I'm wrong but whatever.

UkoKoshka [18]3 years ago

3 0

Answer:

A number line with a closed circle on 3 and shading to the left

Step-by-step explanation:

Equation : $5(x+2)\geq (7x+2(x-1)$

$5x+10 \geq 7x+2x-2$

$12 \geq 4x$

Divide by 4 both sides

$3 \geq x$

So, $x\leq 3$

So, Therefore, the solution set is:

(-∞, 3]

So, A number line with a closed circle on 3 and shading to the left

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Locate the points of discontinuity in the piecewise function shown below.

algol13

Answer:

Step-by-step explanation:

The given piecewise function i

From the given function it is clear that function is divided at x=-1 and x=2. It means we check the discontinuity at x=-1 and x=2.

For x=-1,

LHL:

Since LHL ≠ f(-1), therefore the given function is discontinuous at x=-1.

For x=2,

LHL:

Since LHL ≠ f(2), therefore the given function is discontinuous at x=2.

Therefore, the correct option is A.

8 0

3 years ago

Find the distance between the two points rounding to the nearest tenth (if necessary).

Virty [35]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{9})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(1-3)^2+(9-6)^2}\implies d=\sqrt{(-2)^2+3^2} \\\\\\ d=\sqrt{13}\implies d\approx 3.6056\implies \stackrel{\textit{rounded up}}{d=3.6}$