They are all the same number
Answer:
2. ![\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%5C%5C0%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
3. ![\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%2621%2660%5C%5C-15%269%26-45%5C%5C%5Cend%7Barray%7D%5Cright%5D)
4. ![\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-14%5C%5C-2%26-6%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
2. This matrix is easy, as it just requires addition.
+ ![\left[\begin{array}{ccc}0&0\\0&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
3. This matrix requires for the matrices to be multiplied first, then added.
![\left[\begin{array}{ccc}9&-15&18\\-27&15&-9\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-15%2618%5C%5C-27%2615%26-9%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}-12&36&42 \\12& -6 & -36 \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-12%2636%2642%20%5C%5C12%26%20-6%20%26%20-36%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
4. Here we can add the last 2 matrices to find x.
![\left[\begin{array}{ccc}2&-8\\-4&2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-8%5C%5C-4%262%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}4&-6\\2&-8 \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-6%5C%5C2%26-8%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
Hope this helps! (Please consider giving brainliest)
Answer: YOU TUTOR 9 HOURS
Step-by-step explanation: EACH BOX REPRESENTS 3 HOURS I THINK, SO YOU TUTOR NINE HOURS AND YOUR FRIEND TUTORS 3 HOURS.
3X3=9
1X3=3
Answer:
Wow I got the first step
are you looking for the
intersection of the line perpendicular
to plane 1 thorough the origin and plane 2
for the first part???
Answer:
<h2>
CYLINDER</h2>
Surface Area = 471.2 cm^2
<h2>
TRIANGULAR PRISM</h2>
Surface Area = 60.75 m^2
Step-by-step explanation:
<h2>
CYLINDER</h2>
The surface area formula for a cylinder is π x diameter x (diameter / 2 + height), where (diameter / 2) is the radius of the base (d = 2 x r), so another way to write it is π x radius x 2 x (radius + height). ( π =3.14 )
FORMULA:
π x 5 x 2 x 15
WORK:
π x 5 = 15.7
15.7 x 2 = 31.4
31.4 x 15 = 471
<h2>
TRIANGULAR PRISM</h2>
The surface area formula for a triangular prism is 2 * (height x base / 2) + length x width1 + length x width2 + length x base.
FORMULA:
2 x (2.5 x 1.5/2) + (6 x 4) + (6 x 4) + (6 x 1.5)
WORK:
(2.5 x 1.5) = 3.75/2 = 1.875
1.875 x 2 = 3.75
(6 x 4) = 24
(6 x 4) = 24
(6 x 1.5) = 9
3.75 + 24 + 24 + 9 = 60.75
