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kykrilka [37]
3 years ago
9

A sample of neon gas at 1.20 atm compresses from 0.250 l to 0.125 l. if the temperature remains constant, what is the final pres

sure
Chemistry
1 answer:
Naddika [18.5K]3 years ago
5 0
<h3><u>Answer;</u></h3>

2.4 atm

<h3><u>Explanation;</u></h3>

At constant temperature;

PV = constant  

P1 = 1.2 atm

V1 = 0.25 L

P2 = ?

V2 = 0.125 L

But;

P1*V1 = P2*V2

Thus;

P2 = P1*V1/V2

     = (1.2 atm)(0.25 L)/(0.125 L)

    <u> = 2.4 atm</u>

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