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2 years ago

9

A sample of neon gas at 1.20 atm compresses from 0.250 l to 0.125 l. if the temperature remains constant, what is the final pres

sure

1 answer:

Naddika [18.5K]2 years ago

5 0

<h3><u>Answer;</u></h3>

2.4 atm

<h3><u>Explanation;</u></h3>

At constant temperature;

PV = constant

P1 = 1.2 atm

V1 = 0.25 L

P2 = ?

V2 = 0.125 L

But;

P1*V1 = P2*V2

Thus;

P2 = P1*V1/V2

= (1.2 atm)(0.25 L)/(0.125 L)

<u> = 2.4 atm</u>

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