Answer:
The formula defining the photon energies that would be emitted by transitions between the hydrogen energy levels are given by the equation:
ΔE = -13.6Z²[1/n₁² - 1/n₂²]eV, where (1 eV = 1.602×10-19 Joules) and n₁ = initial energy level and n₂ = final energy level.
Z = Atomic number of the atom
<h3>The average atomic mass of Iodine : 126.86 amu</h3><h3>Further explanation</h3>
Given
80% 127I, 17% 126I, and 3% 128I.
Required
The average atomic mass
Solution
The elements in nature have several types of isotopes
Atomic mass is the average atomic mass of all its isotopes
Mass atom X = mass isotope 1 . % + mass isotope 2.% + ... mass isotope n.%
Atomic mass of Iodine = 0.8 x 127 + 0.17 x 126 + 0.03 x 128
Atomic mass of Iodine = 101.6 + 21.42 + 3.84
Atomic mass of Iodine = 126.86 amu
Answer:
The last region should be right
Explanation:
