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wlad13 [49]
2 years ago
14

A student adds hydrobromic acid (HBr) to a solution of sodium bromide at equilibrium. How does this change affect the system?

Chemistry
1 answer:
egoroff_w [7]2 years ago
4 0

The addition of bromine would cause the equilibrium to shift towards the reactant's side.

<h3>Equilibrium</h3>

When a reaction is in equilibrium and one of the constraints that affect the rate of reactions is applied, the equilibrium shifts so as to annul the effects of the introduced constraints.

Thus, for the reaction

NaBr(s) ⇌ Na+(aq) + Br−(aq)

The addition of HBr would introduce more Br- into the reaction. Consequently, the equilibrium will shift to produce more NaBr so as to annul the effects of the addition of Br-

More on equilibrium can be found here:  brainly.com/question/4289021

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Which of the following pairs of elements is most likely to form an ionic compound?
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In the laboratory you are asked to make a 0.175 m barium iodide solution using 13.9 grams of barium iodide. How much water shoul
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<u>Answer:</u> The mass of water that should be added in 203.07 grams

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m = molality of barium iodide solution = 0.175 m

m_{solute} = Given mass of solute (barium iodide) = 13.9 g

M_{solute} = Molar mass of solute (barium iodide) = 391.14 g/mol

W_{solvent} = Mass of solvent (water) = ? g

Putting values in above equation, we get:

0.175=\frac{13.9\times 1000}{391.14\times W_{solvent}}\\\\W_{solvent}=\frac{13.9\times 1000}{391.14\times 0.175}=203.07g

Hence, the mass of water that should be added in 203.07 grams

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3 years ago
A molecule consisting of more than one element that are chemically combined.
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compound, but I could be wrong

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