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jenyasd209 [6]
3 years ago
8

Iodine is 80% 127I, 17% 126I, and 3% 128I. Calculate the average atomic mass of Iodine.

Chemistry
1 answer:
trasher [3.6K]3 years ago
6 0
<h3>The average atomic mass of Iodine : 126.86 amu</h3><h3>Further explanation</h3>

Given

80% 127I, 17% 126I, and 3% 128I.

Required

The average atomic mass

Solution

The elements in nature have several types of isotopes

Atomic mass is the average atomic mass of all its isotopes

Mass atom X = mass isotope 1 . % + mass isotope 2.% + ... mass isotope n.%

Atomic mass of Iodine = 0.8 x 127 + 0.17 x 126 + 0.03 x 128

Atomic mass of Iodine = 101.6 + 21.42 + 3.84

Atomic mass of Iodine = 126.86 amu

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Duncan takes a break from studying and goes to the gym to swim laps If swimming burns amount of time ? 85 * 10 ^ 5 cal per hour
Volgvan

When 6.85×10⁵ cal is converted to kilojoules, the result obtained is 2866.04 KJ

<h3>Data obtained from the question </h3>
  • Energy (cal) = 6.85×10⁵ cal
  • Energy (KJ) =?

<h3>Conversion scale </h3>

1 cal = 0.004184 KJ

<h3>How to convert 6.85×10⁵ cal to kilojoules</h3>

1 cal = 0.004184 KJ

Therefore,

6.85×10⁵ cal = 6.85×10⁵ × 0.004184

6.85×10⁵ cal = 2866.04 KJ

Thus, 6.85×10⁵ cal is equivalent to 2866.04 KJ

Learn more about conversion:

brainly.com/question/2139943

6 0
2 years ago
1. What is the potential energy of a 8 kg ball that is at a height of 20 m?
weqwewe [10]

Answer:

1. 1568 J

2. 0 J

3. 1176 J

Explanation:

PE = mgh

(PE = Potential Energy) = (m = mass)(g = gravitational force which is 9.8)(h = height)

1. (3)(9.8)(20) = 1568 J

2. PE = (3)(9.8)(0) = 0 J

3. (5)(9.8)(24) =  1176 J

4 0
3 years ago
Which element is most likely to gain an electron?
Oduvanchick [21]
B. Fluorine (F) is the right answer
3 0
3 years ago
If a piece of matter changes shape, how does its mass change?
kap26 [50]

The law of conservation of mass states that matter cannot be created nor destroyed the answer would be D. It remains the same
5 0
3 years ago
Match each transition metal ion with its condensed ground-state electron configuration. A [Ar]3d2 B [Ar]4s23d3 C [Kr]4d10 D [Xe]
madreJ [45]

Answer:

Mn^{2+} : - F . [Ar]3d^{5}

Hg^{2+} : - G. [Xe]4f^{14}5d^{10}

La^{3+} : - D. [Xe]

Fe^{3+} : - F. [Ar]3d^{5}

Ag^{+} : - C. [Kr]4d^{10}

Co^{3+} : - E. [Ar]3d^{6}

Explanation:

The electronic configuration of the element Mn is:-

[Ar]3d^{5}4s^2

For, Mn^{2+}, 2 electrons are lost, thus the configuration is:-

[Ar]3d^{5}

The electronic configuration of the element Hg is:-

[Xe]4f^{14}5d^{10}6s^2

For, Hg^{2+}, 2 electrons are lost, thus the configuration is:-

[Xe]4f^{14}5d^{10}

The electronic configuration of the element La is:-

[Xe]5d^{1}6s^2

For, La^{3+}, 3 electrons are lost, thus the configuration is:-

[Xe]

The electronic configuration of the element Fe is:-

[Ar]3d^{6}4s^2

For, Fe^{3+}, 3 electrons are lost, thus the configuration is:-

[Ar]3d^{5}

The electronic configuration of the element Ag is:-

[Kr]4d^{10}5s^1

For, Ag^{+}, 1 electron is lost, thus the configuration is:-

[Kr]4d^{10}

The electronic configuration of the element Co is:-

[Ar]3d^{7}4s^2

For, Co^{3+}, 3 electrons are lost, thus the configuration is:-

[Ar]3d^{6}

7 0
3 years ago
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