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Svetlanka [38]
3 years ago
8

How does vegetation slow and prevent sediment loss?

Chemistry
1 answer:
Inga [223]3 years ago
5 0
Vegetation cover is the most effective and practical way to prevent loss of sediment. The roots of vegetation such as grass bind soil particles together to resist erosion especially from runoff water. Vegetation helps absorb the impact of raindrops to prevent detachment of soil particles. Vegetation can flatten act like shingles on a roof, which allows the runoff to flow above the soil. Stiff standing vegetation act as a wind break, reducing wind velocity, such that it is not powerful enough to dislodge sediments from the ground surface.
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You carefully weigh out 16.00 g of CaCO3 powder and add it to 64.80 g of HCl solution. You notice bubbles as a reaction takes pl
bulgar [2K]

Answer: Mass of CO_2  produced in this reaction was 6.56 grams

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

CaCO_3(s)+2HCl(aq)\rightarrow H_2O(l)+CO_2(g)+CaCl_2(aq)

Mass or reactants =  Mass of CaCO_3+ mass of HCl = 16.00 + 64.80 = 80.80 g

Mass of products  = mass of aqueous solution + mass of CO_2 + = 74.24 + x g

Mass or reactants = Mass of products

80.80 g = 74.24 + x g

x = 6.56 g

Thus mass of CO_2  produced in this reaction was 6.56 grams

7 0
3 years ago
When ash, cinders, and bombs build up in a steep pile around a volcano’s vent, the result is a
Verdich [7]
Im pretty sure a cinder-cone volcano 
8 0
3 years ago
How many miles of H2O are produced when 0.322 mol of octane is burned?
victus00 [196]

Answer:

alot of h2o

Explanation:

8 0
3 years ago
How many molecules of ethane are present in 64.28 liters of ethane gas (C2H6) at STP
Rom4ik [11]

Answer : The molecule of ethane present in 64.28 L of ethane gas at STP is, 17.277\times 10^{23} molecule.

Solution :

At STP,

22.4 L volume of ethane present in 1 mole of ethane gas

64.28 L volume of ethane present in \frac{64.28L}{22.4L}\times 1mole=2.869moles of ethane gas

And, as we know that

1 mole of ethane molecule contains 6.022\times 10^{23} molecules of ethane

2.869 moles of ethane molecule contains 2.869\times 6.022\times 10^{23}=17.277\times 10^{23} molecules of ethane

Therefore, the molecule of ethane present in 64.28 L of ethane gas at STP is, 17.277\times 10^{23} molecule.

4 0
3 years ago
Read 2 more answers
An atom X has three electrons in its outermost shell. Which ion will most likely be formed by X?
DedPeter [7]

Answer: X3+

Explanation:

Every atom aim to achieve stability by receiving electrons or giving their valence electrons in order to have a complete outermost shell of 2 (duplet) or 8 (octet structure).

In this case, the atom X will easily give off its three valence electrons to another atom(s), thereby forming a trivalent positive ion (X3+) with a stable duplet or octet structure (i.e an outermost shell with 2 or 8 electrons).

X --> X3+ + 3e-

Thus, due to the give away of three electrons (3e-), the atom X becomes X3+.

6 0
3 years ago
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