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Goshia [24]
3 years ago
7

Based on your energy level calculations, predict the photon energies that would be emitted by transitions between the hydrogen e

nergy levels.
Chemistry
1 answer:
mote1985 [20]3 years ago
8 0

Answer:

The formula defining the photon energies that would be emitted by transitions between the hydrogen energy levels are given by the equation:

ΔE = -13.6Z²[1/n₁² - 1/n₂²]eV, where  (1 eV = 1.602×10-19 Joules) and n₁ = initial energy level  and n₂ = final energy level.

Z = Atomic number of the atom

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The volume of water in a graduated cylinder should be read _________________ the meniscus.
enyata [817]
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The volume of water in a graduated cylinder 
should be read at the bottom of the curve of the meniscus. 
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3 years ago
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A rectangle solid of unknown density is 5 m long two meters high and 4 meters wide. The mass of this solid is 300 grams. Find th
aksik [14]
D= M/V so, D=300/40 wich is 7.5 so D= 7.5g/m3
6 0
3 years ago
When a 6.00 g sample of KBr is dissolved in water in a calorimeter that has a total heat capacity of 2.71 kJ ⋅ K − 1 , the tempe
Umnica [9.8K]

Answer:

Molar heat enthalpy of KBr = -19.89 kJ/mol

Explanation:

Change in temperature (Δt) = 0.370 K

Heat capacity = 2.71 kJ ⋅ K^-1

Heat absorbed by calorimeter = heat capacity × change in temperature

                                               = 2.71× 0.370

                                               = 1.0027 kJ

Molar mass of KBr = 119 g/mol

No. of moles of KBr = 6.00/119

                               = 0.0504 mol

Heat absorbed by the calorimeter is given by KBr.

Now calculate the heat released by per mol of KBr as follows:

Heat released by per mol of KBr = 1.0027 kJ / 0.0504 mol

                                                   =19.89 kJ/mol

Heat is released therefore, sign will be negative.

Molar heat enthalpy of KBr = -19.89 kJ/mol

4 0
3 years ago
a 0.555 g sample of mayonnase was burned in excess oxygen inside a bomb calorimeter with a total heat capacity (bomb and water)
Fofino [41]

Answer:

Dietary\ Calories=65.6kcal

Explanation:

Hello!

In this case, since we can see that the heat released by the combustion of the mayonnaise is absorbed by the bomb calorimeter and water, we can set up the following equation:

m_{mayonnaise}q_{mayonnaise}=C\Delta T

Whereas q for mayonnaise stands for the heat due to its usage; thus, we plug in to obtain:

q_{mayonnaise}=\frac{5.20kJ/\°C*2.93\°C}{0.555g} \\\\q_{mayonnaise}=27.45\frac{kJ}{g}

Now, if 10.0 g are eaten, the energy provided by it turns out:

E_{mayonnaise}=27.45kJ/g*10.0g\\\\E_{mayonnaise}=274.5kJ

And we need that value in dietary calories, 1 kcal:

Dietary\ Calories=274.52kJ*\frac{1kcal}{4.184kJ}\\\\ Dietary\ Calories=65.6kcal

Best regards!

4 0
3 years ago
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Answer: A. Salt in the Dead Sea is saltier
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