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sladkih [1.3K]
3 years ago
14

Three teaspoons of sucrose(17.1 g) is dissolved in hot water to make a total volume of 250 ml solution. Calculate the molarity

Chemistry
1 answer:
dusya [7]3 years ago
5 0
Molar mass sucrose :

C12H22O11 =  342.29 g/mol

number of moles <span>of the solute :
</span>
n = mass solute / molar mass

n = 17.1 / 342.29

n = 0.05 moles

Volume in liters :

250 mL / 1000 =  0.25 L


therefore :

Molarity  =  moles of solute / volume

Molarity =  0.05 / 0.25  => 0.2 mol/L


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Show your calculation by uploading a picture. Calculate the molar mass of ammonia, NH3
Cloud [144]

Answer:

17.04 g/mol

Explanation:

Molar Mass of NH₃

we know that

Nitrogen has 14.01 gram/mol

And Hydrogen has 1.01 gram/mol

but we have 3 Hydrogens So we multiply

1.01 by 3 i.e., 3.03

Now, add

14.01

+<u> </u><u>3</u><u>.</u><u>0</u><u>3</u>

17.04

So, The molar mass of ammonia, NH₃ is

17.04 g/mol

<u>-TheUnknown</u><u>Scientist</u>

5 0
3 years ago
A titration of 25.0 mL of a solution of the weak base aniline, C6H5NH2, requires 25.67 mL of 0.175 M HCl to reach the equivalenc
Lorico [155]

Answer:

a. 0.180M of C₆H₅NH₂

b. 0.0887M C₆H₅NH₃⁺

c. pH = 2.83

Explanation:

a. Based in the chemical equation:

C₆H₅NH₂(aq) + HCl(aq) → C₆H₅NH₃⁺(aq) + Cl⁻(aq)

<em>1 mole of aniline reacts per mole of HCl</em>

Moles required to reach equivalence point are:

Moles HCl = 0.02567L ₓ (0.175mol / L) = 4.492x10⁻³ moles HCl = moles C₆H₅NH₂

As the original solution had a volume of 25.0mL = 0.0250L:

4.492x10⁻³ moles C₆H₅NH₂ / 0.0250L = 0.180M of C₆H₅NH₂

b. At equivalence point, moles of C₆H₅NH₃⁺ are equal to initial moles of C₆H₅NH₂, that is 4.492x10⁻³ moles

But now, volume is 25.0mL + 25.67mL = 50.67mL = 0.05067L. Thus, molar concentration of C₆H₅NH₃⁺ is:

[C₆H₅NH₃⁺] = 4.492x10⁻³ moles / 0.05067L = 0.0887M C₆H₅NH₃⁺

c. At equivalence point you have just 0.0887M C₆H₅NH₃⁺ in solution. C₆H₅NH₃⁺ has as equilibrium in water:

C₆H₅NH₃⁺(aq) + H₂O(l) → C₆H₅NH₂ + H₃O⁺

Where Ka = Kw / Kb = 1x10⁻¹⁴ / 4.0x10⁻¹⁰ =

<em>2.5x10⁻⁵ = [C₆H₅NH₂] [H₃O⁺] / [C₆H₅NH₃⁺]</em>

When the system reaches equilibrium, molar concentrations are:

[C₆H₅NH₃⁺] = 0.0887M - X

[C₆H₅NH₂] = X

[H₃O⁺] = X

Replacing in Ka formula:

2.5x10⁻⁵ = [X] [X] / [0.0887M - X]

2.2175x10⁻⁶ - 2.5x10⁻⁵X = X²

0 = X² + 2.5x10⁻⁵X - 2.2175x10⁻⁶

Solving for X:

X = -0.0015 → False solution. There is no negative concentrations.

X = 0.001477 → Right solution.

As [H₃O⁺] = X, [H₃O⁺] = 0.001477

Knowing pH = -log [H₃O⁺]

pH = -log 0.001477

<h3>pH = 2.83</h3>

7 0
3 years ago
What is the composition of stainless steel​
andreev551 [17]
Stainless steel is an alloy of iron, chromium and nickel.
3 0
1 year ago
Read 2 more answers
The combustion of ________ has added great quantities of carbon dioxide to the atmosphere. Group of answer choices
forsale [732]

Answer:

Fossil fuels.

Explanation:

A fossil fuel is a fuel obtained from nature such as crude oil, coal, wood etc. The burning of fossil fuels releases tremendous amounts of carbon IV oxide into the environment causing a myraid of environmental problems paramount among them is global warming with its attendant consequences.

7 0
3 years ago
If 25.5g of sodium thiosulphate was dissolved in 40g of distilled water at 25°C,
zhenek [66]

Answer:

Formula: Na2S2O3

we get solubility.

Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g .

Solution given:

mass of sodium thiosulphate [m1]=25.5g

mass of water [m2]=40g

at temperature [t]=25°C

we have

<u>solubility in g/dm^3</u> :\frac{solute in gram}{solvent in gram} *100

  • =\frac{25.5}{40}*100
  • =63.75g /litre=63.75g/dm³

<u>solubility in g/dm^3 :63.75g/dm³</u>

<u>n</u><u>o</u><u>w</u>

solubility of the solute in mol/dm^3=:63.75g/dm³/178=0.4 mol/dm³

6 0
3 years ago
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