<u>Answer:</u> The empirical formula for the given compound is 
<u>Explanation:</u>
We are given:
Mass of pure compound containing copper and sulfur = 4.963 g
Mass of S = 1.000 g
Mass of Cu = (4.963 - 1.000) g = 3.963 g
To formulate the empirical formula, we need to follow some steps:
- <u>Step 1:</u> Converting the given masses into moles.
Moles of Copper =
Moles of Sulfur = 
- <u>Step 2:</u> Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0312 moles.
For Copper = 
For Sulfur = 
<u>Step 3:</u> Taking the mole ratio as their subscripts.
The ratio of Cu : S = 2 : 1
Hence, the empirical formula for the given compound is
Answer: 8 moles
Explanation:
C3H8(g) + 5O2(g) ---> 3CO2(g) + 4H2O(g)
The balanced equation above shows the combustion of propane, C3H8 (for x is 3; y is 8) in oxygen, O2 to yield carbon dioxide, CO2 and water, H2O
The mole ratio on combustion are as follows:
5 moles of O2 react to produce 3 moles of CO2
Z mole of O2 react to produce 4.8 moles of CO2
To get the value of Z, cross multiply
4.8 moles x 5 mole = 3 mole x Z
24 = 3Z
Divide both sides by 3
24/3 = 3Z/3
8 = Z
Thus, in the combustion of propane, 8 moles of oxygen (O2) are needed to react to produce 4.8 moles of carbon dioxide (CO2)
Answer:
the type of atom is defined by how many protons, neutrons, and electrons the atom has
Answer:
0.24%
Explanation:
To find the percent error, first subtract the actual value by the expected value. You can ignore the sign of the difference.
42.0 - 42.1 = -0.1 = 0.1
Divide the difference by the expected value and multiply by 100%.
0.1/42.1 = 0.0024 × 100% = 0.24%
The percent error is 0.24%.
