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3 years ago

The term used to describe the rapid release of bubbles from a liquid is _____

1 answer:

5 0

The term used to describe the rapid release of bubbles, or rapid release of a gas from a liquid or a solution is called Effervescence. The bubbling of a solution is due to the escape of a gas which may be from a chemical reaction, as in fermenting liquid, or by coming out of a solution after having been under pressure, as in a carbonated drink. For example; soda, champagne among others.

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A mixture is made by combining 1.62 lb of salt and 5.20 lb of water.

Galina-37 [17]

Answer:

oof idk I would suggest looking at an example and try going off that

7 0

3 years ago

Draw a resonance structure for the cyclopentadienyl anion. Be sure to show all non-bonding electrons and charges explicitly.

Gennadij [26K]

Answer:

The resonance structure for the cyclopentadienyl anion is shown in the drawing below.

Explanation:

The resonance representation of the cyclopentadienyl anion shows that it is a stable ion. On the other hand it is important to note that it has 6 π electrons and is aromatic.

4 0

3 years ago

A rigid 3.80 L sealed vessel contains 0.650 mol Ne, 0.321 mol Kr, and 0.190 mol Xe. Find the density of the mixture in g/L.

Eddi Din [679]

Answer:

17.09g/L

Explanation:

Density = total mass of elements/ volume

We need to find the mass of each mixture constituents using their molar mass:

mole = mass/molar mass

For Neon (Ne) which contains 0.650mol;

0.650 = mass/20.18

mass = 0.650 × 20.18

mass = 13.12g

For Krypton (Kr) which contains 0.321mol;

0.321 = mass/83.79

mass = 0.321 × 83.79

mass = 26.89g

For Xenon (Xe) which contains 0.190mol;

0.190 = mass/131.3

mass = 0.190 × 131.3

mass = 24.95g

Total mass = 13.12g + 26.89g + 24.95g = 64.96g

Density = total mass / volume

Density = 64.96g / 3.80L

Density of the mixture = 17.09g/L

7 0

3 years ago

Select the two chemical reactions that adhere to the law of conservation of matter.

rodikova [14]

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6 0

2 years ago

Charle's Law

Setler [38]

Convert temperature to Kelvin

225°C=498K
127°C=400K

Convert vol to L

400mL=0.4L

Apply Charles law

V1T_2=V2T_1
0.4(400)=498V_2
160=498V_2
V_2=0.32L=320mL

8 0

2 years ago

Read 2 more answers