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Lisa [10]
3 years ago
13

The molar heat of vaporization of water is 40.7 kJ mol . How much heat must be absorbed to convert 50.0 grams of liquid water at

100oC to steam at 100oC?
Chemistry
1 answer:
podryga [215]3 years ago
8 0
Molar mass of water 18g/mol

Number of mols = 50.0g/18g/mol =2.78 mol

 Heat absorbed = 40.7 kj/mol * 2.78 mol = 113.1 kj.
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Can radiation carry thermal energy from object to object?
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Answer:

Radiation is the transfer of thermal energy by waves that can travel through empty space. When the waves reach objects, they transfer thermal energy to the objects.

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What scientists added negatively-charged particles to the model of the atom?
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J.J.Thomson discovered negatively charged particles by cathode ray tube experiment in the year 1897. The particles were name electrons.

3 0
3 years ago
a compound has 15.39 g of gold for every 2.77 g of chlorine. simplified there is _____ g of gold for every 1 g of chlorine
iren [92.7K]

Answer:

There is 5.56 g of gold for every 1 g of chlorine

Explanation:

The ratio is the relationship between two numbers, defined as the ratio of one number to the other. So, the ratio between two numbers a and b is the fraction \frac{a}{b}

You know that a compound has 15.39 g of gold for every 2.77 g of chlorine. This can be expressed by the ratio:

\frac{15.39 g  of gold}{2.77 g of chlorine}

The proportion is the equal relationship that exists between two reasons and is represented by:    \frac{a}{b}=\frac{c}{d}

This reads a is a b as c is a d.

To calculate the amount of gold per 1 g of chlorine, the following proportion is expressed:

\frac{15.39 g  of gold}{2.77 g of chlorine}=\frac{mass of gold}{1 g of chlorine}

Solving for the mass of gold gives:

mass of gold=1 g of chlorine*\frac{15.39 g  of gold}{2.77 g of chlorine}

mass of gold= 5.56 grams

So, <u><em>there is 5.56 g of gold for every 1 g of chlorine</em></u>

5 0
3 years ago
What should go in the blank?
dem82 [27]

Answer:

³⁸₂₀Ca.

Explanation:

³⁸₁₉K –> __ + ⁰₋₁β

Let ʸₓA represent the unknown.

Thus the equation above can be written as:

³⁸₁₉K –> ʸₓA + ⁰₋₁β

Thus, we can obtain the value of y an x as follow:

38 = y + 0

y = 38

19 = x + (–1)

19 = x – 1

Collect like terms

19 + 1 = x

x = 20

Thus,

ʸₓA => ³⁸₂₀A => ³⁸₂₀Ca

Therefore, the equation is:

³⁸₁₉K –> ³⁸₂₀Ca + ⁰₋₁β

6 0
3 years ago
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