Question

The molar heat of vaporization of water is 40.7 kJ mol . How much heat must be absorbed to convert 50.0 grams of liquid water at 100oC to steam at 100oC?

Answer 1

Molar mass of water 18g/mol

Number of mols = 50.0g/18g/mol =2.78 mol

 Heat absorbed = 40.7 kj/mol * 2.78 mol = 113.1 kj.