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Lisa [10]
3 years ago
13

The molar heat of vaporization of water is 40.7 kJ mol . How much heat must be absorbed to convert 50.0 grams of liquid water at

100oC to steam at 100oC?
Chemistry
1 answer:
podryga [215]3 years ago
8 0
Molar mass of water 18g/mol

Number of mols = 50.0g/18g/mol =2.78 mol

 Heat absorbed = 40.7 kj/mol * 2.78 mol = 113.1 kj.
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