Explanation:
i found this the question is different but I think the situation is same
Cation and an anion the differences in charge make them attracted to each other
Answer: Concentration of
in the equilibrium mixture is 0.31 M
Explanation:
Equilibrium concentration of
= 0.729 M
The given balanced equilibrium reaction is,

Initial conc. x 0 0
At eqm. conc. (x-2y) M (y) M (3y) M
The expression for equilibrium constant for this reaction will be:
3y = 0.729 M
y = 0.243 M
![K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5By%5D%5Ctimes%20%5B3y%5D%5E3%7D%7B%5Bx-2y%5D%5E2%7D)
Now put all the given values in this expression, we get :



concentration of
in the equilibrium mixture = 
Thus concentration of
in the equilibrium mixture is 0.31 M
The correct answer is option d, that is, the solubility of a solid is highly dependent on temperature.
Solubility refers to the maximum amount of a component, which will get dissolved in a given concentration of solvent at a particular temperature. The temperature influences the solubility of both gases and solids. The temperature has a direct influence on solubility.
For most of the ionic solids, enhancing the temperature elevates how briskly the solution can be formed. With the increase in temperature, the movement of the solid particles takes place briskly that enhances the chances that they will associate with the majority of the solvent particles. This leads to enhancing the rate at which the solution takes place.