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3 years ago

PLEASE HELP.Which of these substances will dissolve in water?

Chemistry

1 answer:

Alex17521 [72]3 years ago

5 0

Answer:

A. Sugar

Explanation:

Sugar dissolves in water because of its molecular structure (C6H12O6), as the sugar is put in the water, energy is released and the polarity of the water breaks apart the molecules. However, the molecules can be obtained back by evaporating the water.

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What is the theoretical yield of vanadium, in moles, that can be produced by the reaction of 1.0 mole of V2O5 with 4.0 mole of c

yuradex [85]

Answer:

Theoretical moles of V are 1.6 moles

Explanation:

The theoretical yield of a reaction is defined as the amount of product you would make if all of the limiting reactant was converted into product.

In the reaction:

V2O5(s) + 5Ca(i) → 2V(i) + 5CaO(s)

Based on the reaction, 1 mol of V2O5 needs 5 moles of Ca for a complete reaction. As there are just 4 moles, <em>limiting reactant is Ca.</em> As there are produced 2 moles of V per 5mol of Ca, Theoretical moles of V are:

4 moles of Ca × (2mol V / 5Ca) = <em>1.6 moles of V</em>

I hope it helps!

5 0

3 years ago

0. Earth's rock is continually cycling through different states and locations. The diagram below shows the rock cycle. The label

cestrela7 [59]

Answer:

Chemical changes due to heat and pressure

Explanation:

Just took the test, hope this helps! :)

7 0

3 years ago

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A helium balloon with a volume of 550mL is cooled from 305 to 265K. The pressure on the gas is reduced from 0.45 atm to 0.25 atm

Aleksandr [31]

860 mL.

<h3>Explanation</h3>

Separate this process into two steps:

Cool the balloon from 305 K to 265 K.
Reduce the pressure on the balloon from 0.45 atm to 0.25 atm.

What would be the volume of the balloon after each step?

After Cooling the balloon at constant pressure:

By Charles's Law, the volume of a gas is directly related to its temperature in degrees Kelvins.

In other words,

$\dfrac{V_2}{V_1} = \dfrac{T_2}{T_1}$ ,

where

$V_1$ and $V_2$ are volumes of the same gas.
$T_1$ and $T_2$ are the temperatures (in degrees Kelvins) of that gas.

Rearranging,

$V_2 = V_1 \cdot \dfrac{T_2}{T_1}\\\phantom{V_2} = 550 \times \dfrac{265}{305}\\\phantom{V_2} = 478 \; \text{mL}$ .

The balloon ended up with a lower temperature. As a result, its volume drops: $V_2 < V_1$ .

After reducing the pressure on the balloon at constant temperature:

By Boyle's Law, the volume of a gas is inversely proportional to the pressure on this gas.

In other words,

$\dfrac{V_2}{V_1} = \dfrac{P_1}{P_2}$ ,

where

$V_1$ and $V_2$ are volumes of the same gas.
$P_1$ and $P_2$ are the pressures on this gas.

Rearranging,

$V_2 = V_1 \cdot \dfrac{P_1}{P_2}\\\phantom{V_2} = 478 \times \dfrac{0.45}{0.25}\\\phantom{V_2} = 860 \;\text{mL}$ .

There's now less pressure on the balloon. As a result, the balloon will gain in volume: $V_2 > V_1$ .

The final volume of the balloon will be $860 \; \text{mL}$ .

7 0

3 years ago

Is the kool-aid man the jar or the liquid?

nataly862011 [7]

Answer:

I think both

Explanation:

8 0

4 years ago

In a piece of metal, what holds the atoms together?

algol13

The atoms that the electrons leave behind become positive ions, and the interaction between such ions and valence electrons gives rise to the cohesive or binding force that holds the metallic crystal together

7 0

4 years ago

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