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bazaltina [42]
2 years ago
15

PLEASE HELP.Which of these substances will dissolve in water?

Chemistry
1 answer:
Alex17521 [72]2 years ago
5 0

Answer:

A. Sugar

Explanation:

Sugar dissolves in water because of its molecular structure (C6H12O6), as the sugar is put in the water, energy is released and the polarity of the water breaks apart the molecules. However, the molecules can be obtained back by evaporating the water.

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Can someone help Plz
Marrrta [24]

Answer: A. 1.60 liters

Explanation:

2Na_2O_2+2CO_2\rightarrow 2Na_2CO_3+O_2

As can be seen from the balanced chemical equation, 2 moles of CO_2 produce 1 mole of O_2.

According to Avogadro's law, every 1 mole of the gas occupies 22.4 liters at STP.

Thus 2 moles of CO_2 occupies 22.4\times 2=44.8L at STP and produce 1 mole of O_2 i.e. 22.4 L

44.8 L of CO_2 will produce 22.4 L of O_2

Thus 3.20L of CO_2 will produce \frac{22.4}{44.8}\times 3.20=1.60L



6 0
3 years ago
How much heat is released when 15.7g of methane (c2h6) is combusted if the enthalpy of the reaction is - 1560.7 kj
lyudmila [28]

- 407.4 kJ of heat is released.

<u>Explanation:</u>

We have to write the balanced equation as,

2 C₂H₆(g) + 7O₂ → 4CO₂ + 6H₂O

Here 2 moles of ethane reacts in this reaction.

Now we have to find out the amount of ethane reacted using its given mass and molar mass as,

2 mol C₂H₆ × 30.07 g of C₂H₆ / 1 mol C₂H₆ = 60.14 g of C₂H₆

Heat released = ΔH × given mass / 60.14

                        = - 1560. 7 kj ×15.7 g / 60. 14 g  = -407. 4 kJ

5 0
3 years ago
A 720. cm^3 vessel contains a mixture of Ar and Xe. If the mass of the gas mixture is 2.966 g at 25.0°C and the pressure is 760.
sleet_krkn [62]

Explanation:

The given data is as follows.

      Pressure (P) = 760 torr = 1 atm

      Volume (V) = 720 cm^{3} = 0.720 L

     Temperature (T) = 25^{o}C = (25 + 273) K = 298 K

Using ideal gas equation, we will calculate the number of moles as follows.

                                PV = nRT

   Total atoms present (n) = \frac{PV}{RT}

                                          = 1 \times \frac{0.720 L}{0.0821 \times 298}

                                           = 0.0294 mol

Let us assume that there are x mol of Ar and y mol of Xe.

Hence, total number of moles will be as follows.

               x + y = 0.0294

Also,      40x + 131y = 2.966

             x = 0.0097 mol

              y = (0.0294 - 0.0097)

                = 0.0197 mol

Therefore, mole fraction will be calculated as follows.

Mol fraction of Xe = \frac{y}{(x+y)}

                               = \frac{0.0197}{0.0294}

                              = 0.67

Therefore, the mole fraction of Xe is 0.67.

6 0
3 years ago
Na2CrO4 + PbCL2<br> Formula in double replacement
Marta_Voda [28]

Na₂CrO₄ + PbCl₂ → PbCrO₄ + 2 NaCl

<u>Explanation:</u>

In a double displacement reaction, the reactants which are involved in the reaction exchanging their ions thereby produces 2 new compounds. Here sodium chromate and lead chloride are undergoing double displacement reaction, the ions exchanges their position there by forming sodium chloride and lead chromate. So the double displacement reaction is given as,

Na₂CrO₄ + PbCl₂ → PbCrO₄ + 2 NaCl

6 0
3 years ago
Concentrated 8.2 of commercial chloride or chlorox diluted to 14% ?
ELEN [110]
Is it 8.06?

Or 58.57?

Don't get mad if there wrong!!
But please let me know if it's right or wrong tho.
7 0
3 years ago
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