For this reaction to proceed, the following bond breaking should occur:
*one C-O bond* one H-Cl bond
After, the following bond formations should occur:*one C-Cl bond*one O-H bond
Now, add the bond energies for the respective bond energies which can be found in the attached picture. For bond formations, energy is negative. For bond breaking, energy is positive.
ΔHrxn = (1)(358) + (1)(431) + 1(-328) + 1(-463) =
<em> -2 kJ</em>
A. because a chemical change is something that's changing
[Kr]4d3
The configuration of Nb2+ is [Kr]4d3. Nb2+ also has an odd number of valence electrons.