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3 years ago

What is the difference between mass and weight and how they are measured

Physics

2 answers:

Juliette [100K]3 years ago

8 0

Answer:

Mass is the amount of matter in an object. Mass is often measured in kilograms or grams. The masses of two objects are compared using a balance. Weight is the downward pull on an object due to gravity. Weight is often measured in newtons or pounds, using a spring scale.

Explanation:

Just got it right edg. 2020

ololo11 [35]3 years ago

3 0

Answer:

so the differences between both are that the mass is the amount of heaviness in an object or even of you but the weight normally is the mass multiplicated with the gravity of the earth and normally their are measured with this simple formula

M = V . D (mass = volumeby density)

Example

Volume = 3.000 cm³

Density = 3.52 g/cm³

M = 3.000 . 3,52 = 10.560 g

Then you have the weight

To have the result you have to multiplicate the mass and the gravity acceleration

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A 10-cm-thick aluminum plate (α = 97.1 × 10−6 m2/s) is being heated in liquid with temperature of 475°C. The aluminum plate has

Anuta_ua [19.1K]

Answer:

$T_0 = 338.916 Degree\ celcius$

Explanation:

Given data:

Thickness of aluminium sheet 10 cm

initial temperature = 25 degree celcius

Assumption

Thermal properties remain constant, transfer of heat by radiation is negligible.

from the information given in the question we have

T_S ≈T_∞ , it implies we have h → ∞

from table 4.2 Biot number → ∞ the value of

$\lambda_1 = 1.5708 and A_1= 1.2732$

The fourier number is

$t = \frac{\alpha t}{l^2} = \frac{97.1\times 10^{-6} \times 15}{0.05^2} = 0.5826$

Temperature at center after 15 second of heating

$\theta _{0 wall} = \frac{T_0 - T_{\infity}}{T_i -T_{\infity}} = A_i e^{\lambda_1^2 t}$

$T_0 = T_i -T_{\infity} \times A_i e^{\lambda_1^2 t}$

$T_0 = (25 - 475) 1.2732 e^{-1.5708^2 \times 0.5826} + 475 = 356 degree celcius$

$T_0 = 338.916 Degree\ celcius$

8 0

3 years ago

Calculate the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal. Assume that the spe

goblinko [34]

Answer:

the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal is 1835.16 .

Explanation:

We know, wavelength is expressed in terms of Kinetic Energy by :

$\lambda=\dfrac{h}{\sqrt{2mE}}$

Therefore , $E=\dfrac{h^2}{2 \lambda^2 m}$

It is given that both electron and proton have same wavelength.

Therefore,

$E_e=\dfrac{h^2}{2 \lambda^2 m_e}$ .... equation 1.

$E_p=\dfrac{h^2}{2 \lambda^2 m_p}$ .... equation 2.

Now, dividing equation 1 by 2 .

We get ,

$\dfrac{E_e}{E_p}=\dfrac{\dfrac{h^2}{2 \lambda^2 m_e}}{\dfrac{h^2}{2 \lambda^2 m_p}}\\\\\\\dfrac{E_e}{E_p}=\dfrac{m_p}{m_e}$

Putting value of mass of electron = $9.1\times 10^{-31}\ kg$ and mass of proton = $1.67\times 10^{-27}\ kg.$

We get :

$\dfrac{E_e}{E_p}=\dfrac{1.67\times 10^{-27}\ kg}{9.1\times 10^{-31}\ kg}=1835.16$

Hence , this is the required solution.

4 0

4 years ago

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Katie practiced the fuute for 45 minutes then she ate a snack for 15 minutes. next,she watched television for 30 minutes,until 6

Akimi4 [234]

Started at 4.30 p.m ,15+45+30=1 hr 30 mins,6.00-1 hr 30 mins=4.30 p.m

6 0

4 years ago

A stream moving with a speed of 0.5 m/s reaches a point

morpeh [17]

Explanation:

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3 years ago

Help me please!!!!!!!!!!!!!/ Science

Elan Coil [88]

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3 years ago