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3 years ago

Simplify the radical of 10+10

Mathematics

2 answers:

Marianna [84]3 years ago

8 0

10+10=20 the simplified is 2

mina [271]3 years ago

3 0

It should be 20. I hope this helps!!

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26-3=7x (23)
23 divided by 7 =3.2857 (x)

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Mary is buying several items that cost $128.25 total. She is using a store coupon for 35% off her purchases. She has to pay 4% s

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3 years ago

Graph f(x)=3x-1 and g(x)=2^x on the same coordinate plane.

julsineya [31]

Answer:

B. 1 and D. 3.

Step-by-step explanation:

The figure below shows the graphs of f(x) = 3x - 1 (red) and g(x) = 2^x (blue).

The solutions of 3x - 1 = 2^x are the points at which the two curves intersect.

The solutions are at x = 1 and x = 3.

Check:

3 × 1 - 1 = 2¹ 3 × 3 -1 = 2³

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7 0

3 years ago

please help :{ brainliest if you can get it right and I need you to prove why your answer is correct, thanksss

beks73 [17]

Answer:

The Value of $a=\frac{15}{4}$ .

Step-by-step explanation:

We have Named the figure please find the attachment for your reference.

Given:

PR = y

QR = a

RS = b

PS = z

PQ = x

QS = 15

∠P = 90°

∠R = 90°

∠Q = 60°

∠S = 30°

We need to find the Value of 'a'.

Solution:

Now we know that:

In Δ PQS

∠P = 90°

∠S = 30°

Now we know that;

$sin\ \theta = \frac{opposite\ side}{Hypotenuse}$

$sin \ S= \frac{PQ}{QS}$

Substituting the given values we get;

$sin\ 30\°=\frac{x}{15}$

Now we know that;

$sin\ 30\° = \frac12$

So we can say that;

$\frac{1}{2}=\frac{x}{15}\\\\x=\frac{15}{2}$

Now In Triangle PQR.

∠R = 90°

∠Q = 60°

So we can say that;

$Cos \theta = \frac{adjacent \ Side}{Hypotenuse}\\$

$Cos\ Q = \frac{QR}{PQ}$

Substituting the given values we get;

$cos 60\°= \frac{a}{x}$

Now we know that;

$cos 60\°= \frac12$

$x=\frac{15}{2}$

So substituting the values we get;

$\frac{1}{2}=\frac{a}{\frac{15}{2}}$

By Using Cross Multiplication we get;

$a= \frac{1}{2}\times\frac{15}{2}\\\\a=\frac{15}{4}$

Hence The Value of $a=\frac{15}{4}$ .

6 0

3 years ago