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3 years ago

All amino acids contain which of the following groups

Chemistry

1 answer:

anzhelika [568]3 years ago

6 0

Answer:

Explanation:

Amino acid functional groups refer to the amino (~NH3+) and carboxyl (~COOH) group bonded to the alpha carbon. At biological pH (~7.2) the carboxyl will become deprotonated to carboxylate (~COO-). Each amino acid also has a side chain (R group) that may also exhibit functionality.Aug 4, 2015

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Im not sure if it is a molecule or an atom

grigory [225]

Answer:

the first one

Explanation:

I looked it up:P

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3 years ago

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Which subscripts complete the chemical formula for the compound?

tigry1 [53]

Question:

Which subscripts complete the chemical formula for the compound?

Answer:

A: 3

B: 8

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4 years ago

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Arrange the objects in order from least to greatest potential energy. Assume that gravity is constant. (Use PE = m × g × h.) Til

Charra [1.4K]

Answer : The order of potential energy from least to greatest is,

(3) < (1) < (4) < (2)

Explanation :

Formula used :

$P.E=m\times g\times h$

where,

P.E = potential energy

m = mass of an object

g = gravity constant = $9.8m/s^2$

h = height

Now we have to calculate the potential energy of following options.

(1) Tiles a 15-kilogram stone found at a height of 3 meters.

$P.E=15Kg\times 9.8m/s^2\times 3m=441J$

(2) 10 kilograms of water stored at a height of 9 meters.

$P.E=10Kg\times 9.8m/s^2\times 9m=882J$

(3) 1-kilogram ball located 20 meters.

$P.E=1Kg\times 9.8m/s^2\times 20m=196J$

(4) In the area box of books weighing 25 kilograms placed on a shelf 2 meters high.

$P.E=25Kg\times 9.8m/s^2\times 2m=490J$

From this we conclude that, the order of potential energy from least to greatest is,

(3) < (1) < (4) < (2)

4 0

3 years ago

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How many kilojoules of energy would be required to heat a 225g block of aluminum from 23.0 C to 73.5 C?

gulaghasi [49]

Answer:

$\boxed {\boxed {\sf 10.2 \ kJ}}$

Explanation:

We are asked to find how many kilojoules of energy would be required to heat a block of aluminum.

We will use the following formula to calculate heat energy.

$q=mc \Delta T$

The mass (m) of the aluminum block is 225 grams and the specific heat (c) is 0.897 Joules per gram degree Celsius. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature.

ΔT = final temperature - inital temperature

The aluminum block was heated from 23.0 °C to 73.5 °C.

ΔT= 73.5 °C - 23.0 °C = 50.5 °C

Now we know all three variables and can substitute them into the formula.

m= 225 g
c= 0.897 J/g° C
ΔT= 50.5 °C

$q= (225 \ g )(0.897 \ J/g \textdegree C)(50.5 \textdegree C)$

Multiply the first two numbers. The units of grams cancel.

$q= (225 \ g * 0.897 \ J/g \textdegree C)(50.5 \textdegree C)$

$q= (225 * 0.897 \ J / \textdegree C)(50.5 \textdegree C)$

$q= (201.825\ J / \textdegree C)(50.5 \textdegree C)$

Multiply again. This time, the units of degrees Celsius cancel.

$q= 201.825 \ J * 50.5$

$q= 10192.1625 \ J$

The answer asks for the energy in kilojoules, so we must convert our answer. Remember that 1 kilojoule contains 1000 joules.

$\frac { 1 \ kJ}{ 1000 \ J}$

Multiply by the answer we found in Joules.

$10192.1625 \ J * \frac{ 1 \ kJ}{ 1000 \ J}$

$10192.1625 * \frac{ 1 \ kJ}{ 1000 }$

$\frac {10192. 1625}{1000} \ kJ$

$10.1921625 \ kJ$

The original values of mass, temperature, and specific heat all have 3 significant figures, so our answer must have the same. For the number we found, that is the tneths place. The 9 in the hundredth place tells us to round the 1 up to a 2.

$10.2 \ kJ$