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WINSTONCH [101]
3 years ago
9

To determine the molar mass of an unknown organic acid, HA, a 1.056 g sample is titrated with standardized NaOH. Calculate the m

olar mass of HA assuming the acid reacts with 33.78 mL of 0.256 M NaOH. HA is monoprotic.
Chemistry
1 answer:
meriva3 years ago
4 0

Explanation:

Equation for the given reaction is as follows.

     HA(aq) + NaOH(aq) \rightarrow NaA(aq) + H_{2}O(l)

Therefore, moles of NaOH and HA are calculated as follows.

     Moles of NaOH = 0.256 M \times 0.03378 L

                                = 8.64 \times 10^{-3}

                                = 0.00864 mol

     Moles of HA = 0.00864

Also,  moles = \frac{\text{weight}}{\text{molecular weight}}

      Molecular weight = \frac{1.056 g}{0.00864 mol}

                                    = 122.22 g/mol

Thus, we can conclude that molar mass of given unknown organic acid is 122.22 g/mol.

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