<span>B.by arranging the elements according to atomic number instead of atomic mass</span> awnser is B
<h3>
Answer:</h3>
2.125 g
<h3>
Explanation:</h3>
We have;
- Mass of NaBr sample is 11.97 g
- % composition by mass of Na in the sample is 22.34%
We are required to determine the mass of 9.51 g of a NaBr sample.
- Based on the law of of constant composition, a given sample of a compound will always contain the sample percentage composition of a given element.
In this case,
- A sample of 11.97 g of NaBr contains 22.34% of Na by mass
A sample of 9.51 g of NaBr will also contain 22.345 of Na by mass
% composition of an element by mass = (Mass of element ÷ mass of the compound) × 100
Mass of the element = (% composition of an element × mass of the compound) ÷ 100
Therefore;
Mass of sodium = (22.34% × 9.51 g) ÷ 100
= 2.125 g
Thus, the mass of sodium in 9.51 g of NaBr is 2.125 g
Answer:
So, 10 mole of water will weigh (18x10) = 180g.
Answer:
B. flourine
Flourine is the 9th element in the periodic table
Answer:
<h2>∞∞∞∞∞∞║⊕║Hello Person║⊕║∞∞∞∞∞∞</h2>
Your answer should be:
<em>1. No </em>
<em>2. Yes</em>
<em>3. No</em>
<em>4. Yes</em>
<em>5. No</em>
Explanation:
I hope this answered your question.
<em>Brainliest would be appreciated! </em>
<em>Have a wonderful day!</em>
