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2 years ago

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How to balance chemical equations

1 answer:

Monica [59]2 years ago

8 0

To balance a chemical equation, start by writing down the number of atoms in each element, which is listed in the subscript next to each atom. Then, add coefficients to the atoms on each side of the equation to balance them with the same atoms on the other side.

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HELP!! URGENT!! WILL GIVE BRAINIEST

nadya68 [22]

Answer:

11. Mn (CH 3 CO 2) 2. (H 2 O) n where n = 0, 2, 4.

12. Au2O

Explanation:

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3 years ago

What type of compound is formed by the transfer of electrons from one atom to another?

Alex777 [14]

Answer:

ionic compound

Explanation:

ionic bonding

In ionic bonding, electrons are completely transferred from one atom to another. In ionic bonding, electrons are completely transferred from one atom to another. In the process of either losing or gaining negatively charged electrons, the reacting atoms form ions.

pls vote brainliest it would rlly help me out ❤❤❤

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3 years ago

Convert 12 kcal to joules

miss Akunina [59]

Answer:

50241.6

Explanation

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3 years ago

Read 2 more answers

In thermodynamics, we determine the spontaneity of a reaction by the sign of ΔG. In electrochemistry, spontaneity is determined

faltersainse [42]

<u>Answer:</u>

<u>For A:</u> The standard cell potential of the reaction is 4.4 V

<u>For B:</u> The standard Gibbs free energy of the reaction is $-8.50\times 10^5J$

<u>For C:</u> The reaction is spontaneous as written.

<u>Explanation:</u>

<u>For A:</u>

The given chemical reaction follows:

$2Li(s)+Cl_2(g)\rightarrow 2Li^+(aq.)+2Cl^-(aq.)$

The given half reaction follows:

<u>Oxidation half reaction:</u> $Li(s)\rightarrow Li^+(aq.)+e^-;E^o_{Li^+/Li}=-3.04V$ ( × 2)

<u>Reduction half reaction:</u> $Cl_2(g)+2e^-\rightarrow 2Cl^-(aq.);E^o_{Cl_2/2Cl^-}=+1.36V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction.

Here, chlorine will undergo reduction reaction will get reduced.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=1.36-(-3.04)=4.4V$

Hence, the standard cell potential of the reaction is 4.4 V

<u>For B:</u>

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

where,

n = number of electrons transferred = $2mol\text{ e}^-$

F = Faradays constant = $96500J/V.mol\text{ e}^-$

$E^o_{cell}$ = standard cell potential = 4.4 V

Putting values in above equation, we get:

$\Delta G^o=-2\times 96500\times 4.4=-849200J=-8.50\times 10^5J$

Hence, the standard Gibbs free energy of the reaction is $-8.50\times 10^5J$

<u>For C:</u>

For a reaction to be spontaneous, the standard Gibbs free energy change of the reaction must be negative.

From above, the standard Gibbs free energy change of the reaction is coming out to be negative.

Hence, the reaction is spontaneous as written.

7 0

3 years ago

What two things combine with oxygen to form ground-level ozone?

STALIN [3.7K]

Answer:

c) NOx and VOC

oxides of nitrogen (NOx) and volatile organic compounds (VOC)

Explanation:

-

4 0

3 years ago