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storchak [24]
3 years ago
12

How to balance chemical equations

Chemistry
1 answer:
Monica [59]3 years ago
8 0
To balance a chemical equation, start by writing down the number of atoms in each element, which is listed in the subscript next to each atom. Then, add coefficients to the atoms on each side of the equation to balance them with the same atoms on the other side.
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The half-life of tritium (H-3) is 12.3 years. If 48.0mg of tritium is released from a nuclear power plant during the course of a
Rudiy27

Answer:

The amount left after 49.2 years is 3mg.

Explanation:

Given data:

Half life of tritium = 12.3 years

Total mass pf tritium = 48.0 mg

Mass remain after 49.2 years = ?

Solution:

First of all we will calculate the number of half lives.

Number of half lives = T elapsed/ half life

Number of half lives =  49.2 years /12.3 years

Number of half lives =  4

Now we will calculate the amount left after 49.2 years.

At time zero 48.0 mg

At first half life = 48.0mg/2 = 24 mg

At second half life = 24mg/2 = 12 mg

At 3rd half life = 12 mg/2 = 6 mg

At 4th half life =  6mg/2 = 3mg

The amount left after 49.2 years is 3mg.

6 0
4 years ago
The boiling point and distillation temperature of a substance are the same. true false
Novosadov [1.4K]
The boiling point and distillation temperature of a substance are the same. The answer would be True
3 0
3 years ago
A city's water supply is contaminated with a toxin at a concentration of 0.63 mg/L. For the water to be safe for drinking, the c
Shalnov [3]

Answer:

Approximately 22.37 days, will it take for the water to be safe to drink.

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

k is rate constant

Given that:- k = 0.27 (day)⁻¹

[A_0] = 0.63 mg/L

[A_t]=1.5\times 10^{-3} mg/L

Applying in the above equation as:-

1.5\times 10^{-3}=0.63e^{-0.27\times t}

63e^{-0.27t}=150\times \:10^{-3}

e^{-0.27t}=\frac{1}{420}

t=\frac{100\ln \left(420\right)}{27}=22.37

<u>Approximately 22.37 days, will it take for the water to be safe to drink.</u>

7 0
3 years ago
Zn + H2SO4 ZnSO4 + H2<br><br> The mole ratio of zinc to zinc sulfate is
ValentinkaMS [17]

Answer:

Ratio is 1:1

Explanation:

I do not see any coefficients infront of the reactants and the products, therefore, we can automatically assume that every reactant and product is 1 mole. Don't get confused by the 4 off the O. It just means that 1 mole of sulfate has 1 zinc and 4 oxygens.

6 0
3 years ago
Arsenate (AsO43-) is structurally and chemically similar to inorganic phosphate (PO43-), and many enzymes that act on phosphate
Lapatulllka [165]

Answer:

A) The effect on the net reaction catalyzed by glyceraldehyde is that

The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )

B) There will be  no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived

C ) Arsenate is very toxic to most organisms and it is used mostly regarded  as poisons during the formation of glycolysis, it forms  1-arsen0, 3-phosphoglycerate which  hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells

Explanation:

A) The effect on the net reaction catalyzed by glyceraldehyde is that

The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )

B) There will be  no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived

C ) Arsenate is very toxic to most organisms and it is mostly regarded as  poisons during the formation of glycolysis, it forms  1-arsen0, 3-phosphoglycerate which  hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells

4 0
3 years ago
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