Lead (II) chloride+ potassium nitrate
PbCI2+KNO3(B)
<span>Nitric acid is often manufactured from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming of natural gas, in a two-step process. In the first step, nitrogen and hydrogen react to form ammonia:
In the second step, ammonia and oxygen react to form nitric acid and water:</span>
Answer:
- CFJA17
- THZ561
- GJA561
- GH68
- N461
- DG56
- BSJ57
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Answer:
The unknown amount of potassium chloride is 13.6 grams.
Explanation:
The reaction of 14 grams of KNO₃ with KCl produces a total mass of 27.6 grams of the products.
The law of conservation of mass tells us that the total mass of the reactants must be the same that the total mass of the products. So, we can find the mass of KCl as follows:

Where <em>r</em> is for reactants and <em>p </em>is for products



Therefore, the unknown amount of potassium chloride is 13.6 grams.
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Answer:
solubility of X in water at 17.0
is 0.11 g/mL.
Explanation:
Yes, the solubility of X in water at 17.0
can be calculated using the information given.
Let's assume solubility of X in water at 17.0
is y g/mL
The geochemist ultimately got 3.96 g of crystals of X after evaporating the diluted solution made by diluting the 36.0 mL of stock solution.
So, solubility of X in 1 mL of water = y g
Hence, solubility of X in 36.0 mL of water = 36y g
So, 36y = 3.96
or, y =
= 0.11
Hence solubility of X in water at 17.0
is 0.11 g/mL.