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3 years ago

If A and B are two objects with masses 6 kg and 34 kg respectively then

Physics

1 answer:

Mademuasel [1]3 years ago

4 0

Answer:

the object B has more mass (= 34 kg) than the object A (= 6 kg)................................ ᕦ( ᐛ )ᕡ

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Bingel [31]

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3 years ago

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The weight of an object is the product of its mass, mmm, and the acceleration of gravity, ggg (where g=9.8 m/s2g=9.8 m/s2). If a

Andre45 [30]

Answer:

Weight of the object will be 98 N

Explanation:

We have given mass of the object m = 10 kg

Acceleration due to gravity $g=9.8m/sec^2$

We have to find the weight of the object

Weight of the object is dependent on mass and acceleration due to gravity, it is the product of mass and acceleration due to gravity

So weight of the object W = mass × acceleration due to gravity

So $W=10\times 9.8=98N$

So weight of the object will be 98 N

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4 years ago

Equation: S=D]

Ahat [919]

The speed of car is 106.67 miles per hour

To solve problems involving speed and distance we are required to first find speed or distance travelled in an hourly timeframe

It is given that car takes 4 hours to cover the distance at a speed of 40 miles per hour

Therefore, total distance travelled by the car= speed x time

= 40 miles per hour x 4 hour

=160 miles

We are required to find the speed of the car if the distance is to be covered in 1.5 hours

We are required to find the speed by the formula speed= Distance/time

distance= 160 miles time = 1.5 hour

speed= 160/1.5=106.666=106.67 miles per hour

Hence the speed is 106.67 miles per hour

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2 years ago

The Venn diagram compares protons with neutrons. Which shared property belongs in the region marked "B"?

telo118 [61]

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3 years ago

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A low orbit satellite at 100 km altitude had a camera that resolved a car location to within 0.3 meter. Find the minimum diamete

NeX [460]

Answer:

Minimum diameter of the camera lens is 22.4 cm

The focal length of the camera's lens is 300cm

Explanation:

y = Resolve distance = 0.3 m

h = Height of satellite = 100 km

λ = Wavelength = 550 nm

Angular resolution

$tan\theta\approx \theta =\frac{y}{h}\\\Rightarrow \theta=\frac{0.3}{100\times 10^3}=3\times 10^{-6}$

From Rayleigh criteria

$sin\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{sin\theta}\\\Rightarrow D=1.22\frac{550\times 10^{-9}}{sin3\times 10^{-6}}=0.2236\ m=22.4\ cm$

Minimum diameter of the camera lens is 22.4 cm

Relation between resolvable feature, focal length and angular resolution

$d=f\Delta \theta\\\Rightarrow f=\frac{d}{\Delta \theta}\\\Rightarrow f=\frac{9\times 10^{-6}}{3\times 10^{-6}}=3\ m=300\ cm$

The focal length of the camera's lens is 300cm

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3 years ago