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Veseljchak [2.6K]
3 years ago
5

Anyone know how to select someone as brainiest?!!!!!!!!!!!!!!!

Physics
2 answers:
Zepler [3.9K]3 years ago
7 0
Where’s the work????????
Bingel [31]3 years ago
3 0
You press the button near their answer
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Find the velocity of the student using KE= 1/2 mv^2. A 50-kilogram student is running and has 225 joules of kinetic energy. The
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225 = 25 (v2)
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What's formular for calculating a mass <br>​
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force times gravity (FG) =mass times gravity (mg)

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A force of 8480 N is applied to a cart or decelerate is at a rate of 32.0 m/s2. What is the mass of the cart?
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WGVU-AM is a radio station that serves the Grand Rapids, Michigan area. The main broadcast frequency is 1480kHz. At a certain di
Yuki888 [10]

Answer:

a

  \lambda  =  202.7 \  m

b

  w =  9.3 *10^{6} \  rad/s

c

  k = 0.031 m^{-1}

d

  E_{max} = 9.0 *10^{-3} \  V/m

Explanation:

From the question we are told that  

       The frequency of the radio station is  f=  1480 \  kHz  =  1480 *10^{3}\ Hz

         The magnitude of the magnetic field is  B  =  3.0* 10^{-11} \  T

Generally the wavelength is mathematically represented as

          \lambda  =  \frac{c}{f}

Here c is the speed of light with value  c =  3.0 *10^{8} \ m/s

So

        \lambda  =  \frac{3.0 *10^{8}}{ 1480 *10^{3}}

=>      \lambda  =  202.7 \  m

Generally the angular frequency is mathematically represented as

       w =  2 \pi * f

=>   w =  2 * 3.142 *  1480 *10^{3}

=>   w =  9.3 *10^{6} \  rad/s

Generally the wave number is mathematically represented as        

=>      k = \frac{2 \pi }{\lambda}

=>      k = \frac{2  *  3.142  }{ 202.7}

=>      k = 0.031 m^{-1}

Generally the amplitude of the electric field at this distance from the transmitter is mathematically represented as

         E_{max} = c *  B

=>      E_{max} = 3.0 *10^{8} *   3.0* 10^{-11}

=>      E_{max} = 9.0 *10^{-3} \  V/m

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3 years ago
If energy decreases in one part of a system, what will happen?
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C. because energy can not be created or destroyed, but transformed/transferred to maintain equilibrium.
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