Answer:
2.45 J
Explanation:
The following data were obtained from the question:
Mass (m) = 0.5 kg
Height (h) = 1 m
Kinetic energy (KE) =?
Next, we shall determine the velocity of the rock after it has fallen half way. This can be obtained as follow:
Initial velocity (u) = 0 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 1/2 = 0.5 m
Final velocity (v) =? 
v² = u² + 2gh
v² = 0² + (2 × 9.8 × 0.5)
v² = 9.8
Take the square root of both side 
v = √9.8
v = 3.13 m/s
Finally, we shall determine the kinetic energy of the rock after it has fallen half way. This can be obtained as follow:
Mass (m) = 0.5 kg
Velocity (v) = 3.13 m/s
Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 0.5 × 3.13²
KE = 0.25 × 9.8
KE = 2.45 J
Therefore, the kinetic energy of the rock after it has fallen half way is 2.45 J
 
        
             
        
        
        
Answer:
true
Explanation:
this is the answer to this question
 
        
             
        
        
        
Answer:
Explanation:
(a) Work done, W = 1.82 x 10^4 J 
(b) internal energy, U = - 4.07 x 10^4 J ( as it decreases)
(c) According to the first law of thermodynamics  
Q = W + U
Q = 1.82 x 10^4 - 4.07 x 10^4 
Q = - 2.25 x 10^4 J
 
        
             
        
        
        
Answer:
A) 140 k 
b ) 5.22 *10^3 J
c) 2910 Pa 
Explanation:
Volume of Monatomic ideal gas = 1.20 m^3
heat added ( Q ) = 5.22*10^3 J 
number of moles  (n)  = 3 
A ) calculate the change in temp of the gas 
since the volume of gas is constant no work is said to be done 
heat capacity of an Ideal monoatomic gas ( Q ) = n.(3/2).RΔT
make ΔT subject of the equation
ΔT = Q / n.(3/2).R 
     = (5.22*10^3 ) / 3( 3/2 ) * (8.3144 J/mol.k )
     = 140 K 
B) Calculate the change in its internal energy 
ΔU = Q  this is because no work is done 
therefore the change in internal energy = 5.22 * 10^3 J
C ) calculate the change in pressure 
applying ideal gas equation 
P = nRT/V 
therefore ; Δ P = ( n*R*ΔT/V ) 
                         = ( 3 * 8.3144 * 140 ) / 1.20 
                         = 2910 Pa