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4 years ago

PLEASE HELP I WILL GIVE 50 POINTS!

Mathematics

1 answer:

Anastaziya [24]4 years ago

3 0

Answer:

Domain: x is all real numbers

Range: y is less than or equal to 5

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Helppppppp................

GarryVolchara [31]

16 hope this helps you

5 0

4 years ago

Kim was solving a problem using the six steps. First, she read the problem. Then she wrote down the facts and figures. Next, she

tia_tia [17]

The answer would be 1 1/5

48/40 = 1 8/40

1 8/40 Simplify to 1 1/5

Hope this helps!

PLZ GIVE ME BRAINLIEST

8 0

3 years ago

Read 2 more answers

Solve the following proportion: k/4=33/20

Gala2k [10]

Step-by-step explanation:

k/4=33/20

k=33/20×4

k=33/5

6 0

3 years ago

Read 2 more answers

G verify that the divergence theorem is true for the vector field f on the region

Alenkasestr [34]

$\mathbf f(x,y,z)=\langle z,y,x\rangle\implies\nabla\cdot\mathbf f=\dfrac{\partial z}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial x}{\partial z}=0+1+0=1$

Converting to spherical coordinates, we have

$\displaystyle\iiint_E\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=6}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=288\pi$

On the other hand, we can parameterize the boundary of $E$ by

$\mathbf s(u,v)=\langle6\cos u\sin v,6\sin u\sin v,6\cos v\rangle$

with $0\le u\le2\pi$ and $0\le v\le\pi$ . Now, consider the surface element

$\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\dfrac{\mathbf s_v\times\mathbf s_u}{\|\mathbf s_v\times\mathbf s_u\|}\|\mathbf s_v\times\mathbf s_u\|\,\mathrm du\,\mathrm dv$
$\mathrm d\mathbf S=\mathbf s_v\times\mathbf s_u\,\mathrm du\,\mathrm dv$
$\mathrm d\mathbf S=36\langle\cos u\sin^2v,\sin u\sin^2v,\sin v\cos v\rangle\,\mathrm du\,\mathrm dv$

So we have the surface integral - which the divergence theorem says the above triple integral is equal to -

$\displaystyle\iint_{\partial E}\mathbf f\cdot\mathrm d\mathbf S=36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv$
$=\displaystyle36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}(12\cos u\cos v\sin^2v+6\sin^2u\sin^3v)\,\mathrm du\,\mathrm dv=288\pi$

as required.

3 0

4 years ago

This is my last question can someone help me with my homework.

shutvik [7]

9514 1404 393

Answer:

C, A, A

Step-by-step explanation:

In general, you ...

identify the coefficients of one of the variables
swap them, and negate one of them
multiply the corresponding equations by the "adjusted" coefficients.

In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:

multiply equation 2 by -4 . . . (eliminates x)

Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:

multiply equation 1 by 3 . . . (eliminates y)

These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.

The other problems are worked in a similar fashion.

8 0

3 years ago