Answer:
4) m: 1.25 b: 6 Equation: y= 1.25x + 6
5) m: 20 b: 10 Equation: y= 40x + 10
6) m: -2 b: 0 Equation: y= -2x + 0
7) m: 1/5 b: 1 Equation: y= 1/5x + 1
8) -8.7 = 1.3x + 0
I really hope this helps!
The dimensions that would result to maximum area will be found as follows:
let the length be x, the width will be 32-x
thus the area will be given by:
P(x)=x(32-x)=32x-x²
At maximum area:
dP'(x)=0
from the expression:
P'(x)=32-2x=0
solving for x
32=2x
x=16 inches
thus the dimensions that will result in maximum are is length=16 inches and width=16 inches
(2-c,y) is the answer for the problem.
C)3n-2 Im pretty sure.
sorry if it’s wrong <3
