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larisa [96]
3 years ago
6

How much work is done to push a car 20m using a 200 N force?

Physics
1 answer:
Vera_Pavlovna [14]3 years ago
7 0

Answer:

F=200N d=20m t=30s

W=F*d

W=200*20

W=4000J

P=W/t

P=4000/30

P=400/3

P=133.333333334 W

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3 years ago
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2 Points
Mademuasel [1]

According to Newton's Second Law of Motion :

The Force acting on an Object is equal to Product of Mass of the Object and Acceleration produced due to the Force.

:\implies  Force acting = Mass of the Object × Acceleration

Given : Force = 50 newton and Mass of the Object = 10 kg

Substituting the respective values in the Formula, we get :

:\implies  50 N = 10 kg × Acceleration

:\implies \mathsf{Acceleration = \dfrac{50\;N}{10\;kg}}

:\implies Acceleration of the Object = 5 m/s²

4 0
3 years ago
The radius of Saturn is about 10 times the radius of Venus and the mass is about 100 times that of Venus. How much larger is the
lora16 [44]

let the mass of Venus is M then mass of Saturn is 100 M

similarly if the radius of Venus is R then the radius of Saturn is 10 R

now the force of gravity on a man of mass "m" at the surface of Venus is given by

F_1 = \frac{GMm}{R^2}

now similarly the gravitational force on the man if he is at the surface of Saturn

F_2 = \frac{G*100M*m}{(10R)^2}

F_2 = \frac{GMm}{R^2}

so here if we divide the two forces

\frac{F_1}{F_2} = 1

so here we can say

F1 = F2

so on both planets the gravitational force will be same

7 0
3 years ago
Tectonic plate movement is the reason why northern California has a very different landscape than southern California. Two diffe
Studentka2010 [4]

Answer:

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3 0
2 years ago
In a physics lab, Asha is given a 10.7 kg uniform rectangular plate with edge lengths 67.3 cm by 53.5 cm . Her lab instructor re
Leya [2.2K]

Answer:

I=2.6363\ kg.m^2

Explanation:

Given:

dimension of uniform plate, (0.673\times 0.535)\ m^2

mass of plate, m=10.7\ kg

Now we find the moment of inertia about the center of mass of the rectangular plate is given as:

I_{cm}=\frac{1}{12} \times m(L^2+B^2)

where:

L= length of the plate

B= breadth of the plate

I_{cm}=\frac{1}{12} \times 10.7\times(0.673^2+0.535^2)

I_{cm}=0.6591\ kg.m^2

We know that the center of mass of the rectangular plane is at its geometric center which is parallel to the desired axis XX' .

Now we find the distance between the center of mass and the corner:

s=\frac{\sqrt{ (0.673^2+0.535^2)}}{2}

s=0.4299\ m

Now using parallel axis theorem:

I=I_{cm}+m.s^2

I=0.6591+10.7\times 0.4299^2

I=2.6363\ kg.m^2

6 0
3 years ago
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