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almond37 [142]
3 years ago
14

Which device manages the flow of current in an electric circuit?

Physics
2 answers:
Nitella [24]3 years ago
8 0

Answer:

a switch

Explanation:

the flow of current in an electric circuit can be managed by a switch.

ss7ja [257]3 years ago
6 0
I would say the switch because it turns it on and off
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A zero-order reaction has a constant rate of 2.30×10−4 M/s. If after 80.0 seconds the concentration has dropped to 1.50×10−2 M,
dolphi86 [110]

Answer:

Initial concentration of the reactant = 3.34 × 10^(-2)M

Explanation:

Rate of reaction = 2.30×10−4 M/s,

Time of reaction = 80s

Final concentration = 1.50×10−2 M

Initial concentration = Rate of reaction × Time of reaction + Final concentration

= 2.30×10−4 M/s × 80s + 1.50×10−2 M = 3.34 × 10^(-2)M

Initial concentration = 3.34 × 10^(-2)M

6 0
3 years ago
The length of a rectangle is 2 cm more than the width. If the area of the rectangle is
damaskus [11]
I would think 10 but I would have to see the picture
3 0
3 years ago
Read 2 more answers
What is the speed of a wave that has a frequency of 6 Hz and a wavelength of 4 m?
notsponge [240]

Answer:

a ) 24 m/s

Explanation:

Given,

Frequency ( f ) = 6 Hz

Wavelength ( λ ) = 4 m

To find : Speed ( v ) = ?

Formula : -

v = f x λ

v

= 4 x 6

= 24 m/s

Therefore, the speed of a wave that has a frequency of 6 Hz and a wavelength of 4 m

is 24 m/s.

4 0
3 years ago
Two charged spheres are 20cm apart and exert an attractive force of 6x10^-9 N on each other. What will be the force of attractio
Travka [436]
The force of attraction between 2 charged spheres can be explained by Coulomb's law,
It states the force of attraction is directly proportional to the magnitudes of the charges and inversely proportional to the square of the distance between the charges.

/F =  \frac{k q_{1}  q_{2} }{ r^{2} }
where F - force of attraction/repulsion
q₁ and q₂ - charges of the 2 spheres 
k - Coulomb's law constant
r - distance between the spheres

In the question given, the charges of the spheres remain constant in both instances, only distance changes. Therefore (kq₁q₂) = c which is a constant 
then F = c / r²
first instance 
6 x 10⁻⁹ N = c/ (20 cm)² ---1)
F = c/(10 cm)² --- 2)
2) / 1)
\frac{F}{6* 10^{-9} } =  \frac{400}{100}
F = 6 x 10⁻⁹ x 4
F = 2.4 x 10⁻⁸ N
8 0
3 years ago
Pay it forward! Answer a questio1) For a positive point charge, the lines radiate ………. . While, for a negative point charge, the
nikitadnepr [17]

Explanation:

1) For a positive point charge, the lines radiate outwards

for a negative point charge, the lines converge inwards

2) F = 2.3 X 10^-26 N

k = 9 X 10^9 N.m²/C

q1 = q2 = e = 1.6 X 10^-19 C

r = ?

F = kq1q2/r²

r² = kq1q2/F

r = √[kq1q2/F ]

r = √0.0100

r = 0.10m

The two protons are 0.10 m apart

3) The unit if electric field intensity is Newton-per-coulomb N/C

7 0
3 years ago
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