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3 years ago

Practicing good human relations skills and having a positive attitude will

2 answers:

7 0

Have a positive effect on you as a human being. Your attitude will improve, your charisma will spread, and you will a better, more well rounded person.

goldfiish [28.3K]3 years ago

4 0

If you practice good human relation skills then you will be more happy, be open, talk more, you will think more positive and a lot more. (these are just <u>some </u>examples)

Hope this will help someone! ;)

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A wheel with radius 36 cm is rotating at a rate of 19 rev/s.(a) What is the angular speed in radians per second? rad/s(b) In a t

Sedaia [141]

(a) 119.3 rad/s

The angular speed of the wheel is

$\omega= 19 rev/s$

we need to convert it into radiands per second. We know that

$1 rev = 2 \pi rad$

Therefore, we just need to multiply the angular speed of the wheel by this factor, to get the angular speed in rad/s:

$\omega = 19 rev/s \cdot (2\pi rad/rev))=119.3 rad/s$

(b) 596.5 rad

The angular displacement of the wheel in a time interval t is given by

$\theta= \omega t$

where

$\omega=119.3 rad$

and

t = 5 s is the time interval

Substituting numbers into the equation, we find

$\theta=(119.3 rad/s)(5 s)=596.5 rad$

(c) 127.3 rad/s

At t=10 s, the angular speed begins to increase with an angular acceleration of

$\alpha = 1.6 rad/s^2$

So the final angular speed will be given by

$\omega_f = \omega_i + \alpha \Delta t$

where

$\omega_i = 119.3 rad/s$ is the initial angular speed

$\alpha = 1.6 rad/s^2$ is the angular acceleration

$\Delta t = 15 s - 10 s = 5 s$ is the time interval

Solving the equation,

$\omega_f = (119.3 rad/s) + (1.6 rad/s^2)(5 s)=127.3 rad/s$

(d) 616.5 rad

The angle through which the wheel has rotated during this time interval is given by

$\theta = \omega_i \Delta t + \frac{1}{2} \alpha (\Delta t)^2$

Substituting the numbers into the equation, we find

$\theta = (119.3 rad/s)(5 s) + \frac{1}{2} (1.6 rad/s^2) (5 s)^2=616.5 rad$

(e) 222 m

The instantaneous speed of the center of the wheel is given by

$v_{CM} = \omega R$ (1)

where

$\omega$ is the average angular velocity of the wheel during the time t=10 s and t=15 s, and it is given by

$\omega=\frac{\omega_i + \omega_f}{2}=\frac{127.3 rad/s+119.3 rad/s}{2}=123.3 rad/s$

and

R = 36 cm = 0.36 m is the radius of the wheel

Substituting into (1),

$v_{CM}=(123.3 rad/s)(0.36 m)=44.4 m/s$

And so the displacement of the center of the wheel will be

$d=v_{CM} t = (44.4 m/s)(5 s)=222 m$

8 0

3 years ago

Two resistors with resistance values of 4.5 Ω and 2.3 Ω are connected in series or parallel across a 30 V potential difference t

Goshia [24]

Answer:

<h2><u>plz mark as a pure substance abuse and function of the equation for sulphur dioxide emissions and function of the equation for sulphur dioxide emissions and function of the equation for sulphur dioxide emissions and function of the equation for sulphur dioxide emissions and function of the equation for </u></h2>

5 0

3 years ago

\. A mixture of gases con-tains oxygen, nitrogen, and water vapor. What physical process could you use to remove the water vapor

Eddi Din [679]

Answer:

Condensation.

Explanation:

The boiling point of water is much higher than that of either nitrogen or oxygen gas . So when the mixture is condensed to a temperature lower than

100°C , water vapor will come out first in the form of water leaving other

elements of mixture in gaseous phase. In this way, water vapor will get separated from others.

3 0

3 years ago

What information do you think the temperatures of stars give us?

Paul [167]

Explanation:

One way of classifying stars is by their temperature .

Science strives to be able to describe how stars and planets form and evolve. This requires theories to describe the processes which include:

Star and planet formation

Star and planet composition

Stellar and solar system evolution

The nuclear processes happening inside stars

The scientific method means that all theories are put to the test. By measuring or calculating the temperature, age and composition of other planets and stars the theories can be tested. If observed values of these parameters are not predicted by theories, then the theories are wrong and need to be revised or replaced.

6 0

3 years ago

Read 2 more answers

A proton is going 2,000 m/s into a magnetic field of 300 T. How much force does it feel. The charge of a proton = 1.602 x 10^-19

NemiM [27]

This depends on the direction of the velocity vector to the magnetic field vector. The force is F=q(VxB) ("x" is the cross product.) The max force is when V and B are perpendicular. Then F=qVB = (1.602e-19)(2000)(300) = 9.612e-14 N

7 0

2 years ago