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tangare [24]
3 years ago
7

If you had to choose to live on the moon or mars, explain why you would choose

Chemistry
1 answer:
FinnZ [79.3K]3 years ago
8 0

Answer:

I would choose to live on mars

Explanation:

I would choose to live on mars because not only is it the most habitable planet in our solar system other than Earth, there is enough gravity on Mars to be believed that our bodies can adapt. It is also not too hot or cold for us. There is soil that water can be extracted from, and we can also use solar panels to collect energy. Although we would have to use advanced technology when going there, but I think these are a few reasons why I would prefer living on Mars over the Moon.

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The four structures that both prokaryotic and eukaryotic cells have are
umka21 [38]

Hello! Greetings from Turkey! :)

<em>* Cell membrane</em>

<em>* Cytoplasm</em>

<em>* DNA and RNA</em>

<em>* Ribosome</em>

                                                                                                     GOOD LUCK!!

8 0
3 years ago
Any suggestions or answers
leva [86]

Explanation: energy levels are three(counting number of cyecles) outer electrons are 3 also

Answer:3,3

6 0
3 years ago
Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia. N2(g)+3H2(g)⟶2NH3(g) Ass
yaroslaw [1]

Answer:

moles of ammonia produced = 0.28 moles

Explanation:

The reaction is

N_{2}(g)+3H_{2}(g) --> 2NH_{3}(g)

As per equation, one mole of nitrogen will react with three moles of hydrogen to give two moles of ammonia

So 0.140 moles of nitrogen will react with = 3 X 0.140 moles of Hydrogen

             = 0.42 moles of hydrogen molecule.

this will give 2 X 0.140 moles of ammonia = 0.28 moles of ammonia

the moles of ammonia produced = 0.28 moles

Here the nitrogen is limiting reagent.

4 0
3 years ago
Be sure to answer all parts. In the average adult male, the residual volume (RV) of the lungs, the volume of air remaining after
Alenkinab [10]

<u>Answer:</u>

<u>For a:</u> The number of moles of air present in the RV is 0.047 moles

<u>For b:</u> The number of molecules of gas is 2.83\times 10^{22}

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the number of moles, we use the equation given by ideal gas follows:

PV=nRT

where,

P = pressure of the air = 1.00 atm

V = Volume of the air = 1200 mL = 1.2 L    (Conversion factor:  1 L = 1000 mL)

T = Temperature of the air = 37^oC=[37+273]K=310K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of air = ?

Putting values in above equation, we get:

1.00atm\times 1.2L=n_{air}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 310K\\n_{air}=\frac{1.00\times 1.2}{0.0821\times 310}=0.047mol

Hence, the number of moles of air present in the RV is 0.047 moles

  • <u>For b:</u>

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules.

So, 0.047 moles of air will contain (0.047\times 6.022\times 10^{23})=2.83\times 10^{22} number of gas molecules.

Hence, the number of molecules of gas is 2.83\times 10^{22}

7 0
2 years ago
How many moles of oxygen are necessary to react completely with four moles of propane (CH)?
steposvetlana [31]

Answer:

20 mole of oxygen

Explanation:

1 mole of proprane reacts with 5 moles of oxygen so 4 time 5 equals 20

7 0
3 years ago
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