Can you take a better picture?
Answer:
(x-4)² + y² = 100
Step-by-step explanation:
The only circles that have a center at (4 , 0) are :
(x-4)² + y² = 100
(x-4)² + y² = 10
……………………
• (-2 - 4)² + 8² = (-6)² + 64 = 36 + 64 = 100 ≠ 10
Then
The circle (x-4)² + y² = 10 doesn’t contain the point (-2, 8)
• (-2 - 4)² + 8² = 100
Then
The circle (x-4)² + y² = 100 contains the point (-2, 8)
Answer: 3.61km or √13
Step-by-step explanation:
Given Data:
Sides of hexagon = 2km each
Distance walked by Ama = 5km
Therefore;
Let Ama starting position be the origin.
With this She would travel along two edges and then go halfway along a third.
Her new x- coordinate would be
= 1 + 2 + 1/2 = 7/2
Because she travels a distance of 5km which translates to 2 and half side of the Hexagon
= 2*1/2
= 1km. On her x-coordinates
For her y-coordinate we use same principles as x-coordinates
= √3 + 0 - √3/2
= √3/2
Therefore her distance walked
= √ ( (7/2)^2 + (√ 3/2)^2 )
= √ ( 49/4 + 3/4 )
= √ 13
= 3.61km
Answer: A (1.156x10(6)
Step-by-step explanation: IM DOING THE INTERIM TOOOOOO
Answer:
Step-by-step explanation:
Look at the picture.
ΔADC and ΔCDB are similar. Therefore the sides are in proportion:
We have
Substitute:
<em>cross multiply</em>
For x use the Pythagorean theorem:
