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Rudiy27
3 years ago
11

Two coils have the same number of circular turns and carry the same current. Each rotates in a magnetic field acting perpendicul

arly to its axis of rotation. Coil 1 has a radius of 4.0 cm and rotates in a 0.21-T field. Coil 2 rotates in a 0.45-T field. Each coil experiences the same maximum torque. What is the radius (in cm) of coil 2
Physics
1 answer:
Delicious77 [7]3 years ago
5 0

Answer:

The radius of coil 2 = 2.7 cm

Explanation:

The number of coils = 2

It is given that both carry equal current and rotates in the magnetic field.

The given radius of coil 1 = 4.0 cm

Coil 1 rotates = 0.21 T field

Coil 2 rotates = 0.45 T filed.

The radius of coil 2 need to be calculated.

Torque action on dipole is given byT =NIABsinθ

here T1 = T2

r1^{2} \times  B1 = r2^{2} \times B2 \\r2^{2} = 0.04 \times 0.04 \times \frac{0.21}{0.45} \\r2 = 0.027m   \ or \ 2.7 cm \\

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Hope this helps!
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What determines how the plates interact at their boundaries
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A 0.20 kg mass attached to the end of a spring causes it to stretch 3.0 cm. What is the spring constant? What is the potential e
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Given that the mass is m = 0.2 kg and the displacement is x = 3 cm = 0.03 m

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The spring constant can be calculated by the formula

\begin{gathered} F=\text{ kx} \\ mg\text{ = kx} \\ k\text{ = }\frac{mg}{x} \end{gathered}

Here, k is the spring constant.

g = 9.8 m/s^2 is the acceleration due to gravity.

Substituting the values, the spring constant will be

\begin{gathered} k=\frac{0.2\times9.8}{0.03} \\ =\text{ 65.33 N/m } \end{gathered}

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8 0
1 year ago
13.
lisov135 [29]

The net torque on the seesaw is 294 Nm.

<h3>What is torque?</h3>

Torque is the force that tends to rotate the body to which it was applied.

To calculate the net torque, we use the formula below

Formula:

  • τ = mgd-m'gd'........... Equation 1

Where:

  • τ = Net torque
  • m = Jenny's mass
  • m' = Tom's mass
  • d = Jenny's distance from the pivot
  • d' = Tom's distance from the pivot
  • g = acceleration due to gravity

From the question,

Given:

  • m = 40 kg
  • m' = 30 kg
  • d = 1.5 m
  • d' = 1 m
  • g = 9.8 m/s²

Substitute these values into equation 1

  • τ = (40×1.5×9.8)-(30×1×9.8)
  • τ  = 588-294
  • τ  = 294 Nm

Hence, The net torque on the seesaw is 294 Nm.

Learn more about torque here: brainly.com/question/14839816

5 0
3 years ago
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