Answer:
Then volume of the balloon will increase to 7.11 L
Explanation:
Step 1:
Data obtained from the question. This includes:
Initial pressure (P1) = 1.05 atm
Initial volume (V1) = 5.0 L
Initial temperature (T1) = 20°C
Final pressure (P2) = 0.65 atm
Final temperature (T2) = –15°C
Final volume (V2) =?
Step 2:
Conversion of celsius temperature to Kelvin temperature. This is illustrated below
K = °C + 273
T1 = 20°C + 273 = 293K
T2 = –15°C + 273 = 258K
Step 3:
Determination of the final volume.
Applying the general gas equation P1V1/T1 = P2V2/T2, the final volume of the balloon can be obtained as follow:
P1V1/T1 = P2V2/T2
1.05 x 5/293 = 0.65 x V2/258
Cross multiply to express in linear form
293 x 0.65 x V2 = 1.05 x 5 x 258
Divide both side by 293 x 0.65
V2 = (1.05 x 5 x 258) / (293 x 0.65)
V2 = 7.11 L
Therefore, the volume of the balloon will increase to 7.11 L when the balloon rises to an altitude where the pressure is 0.65 atm and the temperature is –15° C
