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Wewaii [24]
2 years ago
11

The water in a deep underground well is used as the cold resevoir of a Carnot heat pump that maintains the temperature of a hous

e at 308 K. To deposit 13900 J of heat in the house, the heat pump requires 900 J of work. Determine the temperature of the well water.
Physics
1 answer:
VMariaS [17]2 years ago
6 0

Answer:

The temperature of well water be 288.07 K

Explanation:

We have given Heat in house Q_H=13900J

Work done W = 900 J

Efficiency is given by \eta =\frac{W}{Q_H}=\frac{900}{13900}=0.0647

Efficiency is also given by \eta =1-\frac{T_L}{T_H}, here T_L is lower temperature and T_H is higher temperature

So 0.0647=1-\frac{T_L}{T_H}

0.0647=1-\frac{T_L}{308}

T_L=288.07K

So the temperature of well water be 288.07 K

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Vera_Pavlovna [14]

B. Aluminum is possibly correct

4 0
3 years ago
An object of mass 100kg is raised 2m above the ground using an Inclined Plane of length 10m calculate the effort parallel to inc
MArishka [77]

Answer:

Slope = 2 m / 10 m = 1/5

For every  5 m of effort the object will be raised 1 m

W = work done on object = M g h      increase in PE of object

E S = W      where E is effort and S the distance thru which the effort acts

E S = M g H

E = 100 kg * 9.8 m/s^2 * 2 m / 10 m = 196 kg m / s^2 = 196 N

Check: total work = 2 * 9.8 * 100 = 1960 J

Force Needed = 1960 J / 2 m = 980 Newtons

Mechanical advantage = 980 / 196 = 5   as one would expect since the object is raised 1 m for every 5 m of force input

8 0
2 years ago
IBM has a fast computer that it calls the Blue Gene/L that can do '136.8
dmitriy555 [2]

Answer:

138.6 megacalculations

Explanation:

This is a pretty straightforward one.

All it needs is to convert the degree of measurement.

Dimensions in physics are attributed names, which state the power to which they're are raised. Just as how

Kilo and Mega means the numbers are raised to the power of 3 and 6 respectively. There also exists the ones that indicates how small, such as milli and micro, which are to the powers of -3 & -6.

The question says the IBM computer calculates at an astonishing 136.8 teracalculations.

Tera in physics means it's raised to the power of 12. Thus, the IBM calculates at an astonishing rate of

136.8*10^12 calculations per second.

We're then asked how many calculations it does in 1 micro second. Like I had highlighted earlier, 1 micro second is 1 raised to the power of -6. Or succinctly put,

1 micro second = 1*10^-6.

If the IBM does

138.6*10^12 = 1 second,

Then it does

x = 1*10^-6 second.

When we cross multiply, we have

138.6*10^12 * 1*10^-6, and that is

138.6*10^6 calculations, or say, 138.6 megacalculations.

The IBM does 138.6 megacalculations in 1 micro second, which is still astonishing, by the way

6 0
2 years ago
It's not D
DanielleElmas [232]
A. it provides support
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2 years ago
A major physical disability usually leaves people ________ than able-bodied people with depression. Most patients "locked in" a
Ierofanga [76]

Answer:

happier; do not

Explanation:

A major physical disability usually leaves people __happier______ than able-bodied people with depression. Most patients "locked-in" a motionless body ____do not____ indicate they want to die.

4 0
3 years ago
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