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2 years ago

13.

Physics

1 answer:

lisov135 [29]2 years ago

5 0

The net torque on the seesaw is 294 Nm.

<h3>What is torque?</h3>

Torque is the force that tends to rotate the body to which it was applied.

To calculate the net torque, we use the formula below

Formula:

τ = mgd-m'gd'........... Equation 1

Where:

τ = Net torque

m = Jenny's mass
m' = Tom's mass
d = Jenny's distance from the pivot
d' = Tom's distance from the pivot
g = acceleration due to gravity

From the question,

Given:

m = 40 kg
m' = 30 kg
d = 1.5 m
d' = 1 m
g = 9.8 m/s²

Substitute these values into equation 1

τ = (40×1.5×9.8)-(30×1×9.8)
τ = 588-294
τ = 294 Nm

Hence, The net torque on the seesaw is 294 Nm.

Learn more about torque here: brainly.com/question/14839816

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A projectile is shot directly away from Earth's surface. Neglect the rotation of the Earth. What multiple of Earth's radius RE g

Anna35 [415]

Answer:

a) $r_1=1.36R$

b) $r_2=2.083R$

Explanation:

<u>Given:</u>

a) when the initial velocity of the projectile is 0.520 times the escape velocity from the earth.

Let r be the radial distance from the earth's surface Let M be the mass of the Earth and R be the radius of the Earth

Now using conservation of Energy at earths surface and at distance r we have

$\dfrac{-GMm}{R}+\dfrac{m(0.52V_e)^2}{2}=\dfrac{-GMm}{r_1}\\\dfrac{-GMm}{R}+\dfrac{m\times 0.52^2\times \dfrac{2GM}{R}}{2}=\dfrac{-GMm}{r_1}\\r_2=1.36\ R$

b) when the Initial kinetic Energy of the projectile is 0.52 times the Kinetic Energy required to escape the Earth

Conservation of Energy we have

$\dfrac{-GMm}{R}+0.52\times KE_{escape}=\dfrac{-GMm}{r_2}\\\dfrac{-GMm}{R}+0.52\times\dfrac{m\times \dfrac{2GM}{R}}{2}=\dfrac{-GMm}{r_2}\\r_2=2.083\ R$

3 0

3 years ago

A juggler throws a bowling pin straight up in the air. After the pin leaves his hand and while it is in the air, which statement

WINSTONCH [101]

Answer:

The velocity of the pin is opposite its acceleration on the way up.

(d) option is correct.

Explanation:

when the juggler throws a bowling pin straight in the air, the acceleration working on the pin is in the downward direction due to the gravitational force of the earth.

According to Newton's Universal Law of Gravitation

''The gravitational force is a force that attracts any objects with mass''

8 0

3 years ago

think about something that has happened to you physically—a fall, a jump, an accident, or something you may have done hundreds o

timurjin [86]

My best hobby is driving. Driving has something to do with Newton's first law of motion, which states that an object will continue to be in its state of rest or in uniform motion in a straight line unless it is acted upon by an external force. This law means that an object will continue to be in motion in the same direction unless it is acted upon by a force. Newton's first law of motion is also called the law of inertia.

I usually experience the law of inertia when I am driving my car.

Every morning, for me to move the car from its state of rest to a state of uniform motion, I have to switch on the ignition, which represent an unbalanced force that move the car out of its states of rest. When I am driving, the car continue in motion and in the same direction, unless I apply the brake. The application of the brake is an example of applying an unbalanced force to stop a body in motion.

5 0

3 years ago

Determine the force of gravitational attraction between the Earth and the moon. Their masses are 5.98 x 1024 kg and 7.26 x 1022

monitta

Answer:

$F=1.95\times 10^{20}\ N$

Explanation:

Mass of Earth, $m_e=5.98 \times 10^{24}\ kg$

Mass of Moon, $m_m=7.26\times 10^{22}\ kg$

The distance between Earth and the Moon is, $d=384,400\ km$

We need to find the force of gravitational attraction between the Earth and the moon. The force of gravity is given by :

$F=G\dfrac{m_em_m}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{5.98 \times 10^{24}\times 7.26\times 10^{22}}{(384400 \times 10^3)^2}\\\\F=1.95\times 10^{20}\ N$

So, the required force is $1.95\times 10^{20}\ N$ .

4 0

3 years ago

5. What is the amplitude of the waves shown in the diagram below?

Nitella [24]

Answer:

0.54 m

Explanation:

Example below.

3 0

2 years ago